Linq OrderBy against specific values

Question

Is there a way in Linq to do an OrderBy against a set of values (strings in this case) without knowing the order of the values?

Consider this data:

A         


        

Answer 1

In addition to @Daniel Brückner answer and problem defined at the end of it:

I don't like Concat() and ToList() in there. But for the moment I have no really >good way around that. I am looking for a nice trick to turn the -1 of the first >example into a big number.

I think that the solution is to use a statement lambda instead of an expression lambda.

var data = new List<string> { "corge", "baz", "foo", "bar", "qux", "quux" };
var fixedOrder = new List<string> { "foo", "bar", "baz" };
data.OrderBy(d => {
                    var index = fixedOrder.IndexOf(d);
                    return index == -1 ? int.MaxValue : index; 
                  });

The ordered data is:

foo 
bar 
baz 
corge 
qux 
quux 

Answer 2

Danbrucs solution is more elegant, but here is a solution using a custom IComparer. This might be useful if you need more advanced conditions for your sort ordering.

    string[] svals = new string[] {"A", "B", "A", "C", "B", "C", "D", "E"};
    List<string> list = svals.OrderBy(a => a, new CustomComparer()).ToList();

    private class CustomComparer : IComparer<string>
    {
        private string firstPref = "A";
        private string secondPref = "B";
        private string thirdPref = "C";
        public int Compare(string x, string y)
        {
            // first pref 
            if (y == firstPref && x == firstPref)
                return 0;
            else if (x == firstPref && y != firstPref)
                return -1;
            else if (y == firstPref && x != firstPref)
                return 1;
            // second pref
            else if (y == secondPref && x == secondPref)
                return 0;
            else if (x == secondPref && y != secondPref)
                return -1;
            else if (y == secondPref && x != secondPref)
                return 1;
            // third pref
            else if (y == thirdPref && x == thirdPref)
                return 0;
            else if (x == thirdPref && y != thirdPref)
                return -1;
            else
                return string.Compare(x, y);
        }
    }

Answer 3

Put the preferred values in a dictionary. Looking up keys in a dictionary is a O(1) operation compared to finding values in a list which is a O(n) operation, so it scales much better.

Create a sort string for each preferred value so that they are placed before the other values. For the other values the value itself will be used as sorting string so that they are actually sorted. (Using any arbitrary high value would only place them at the end of the list unsorted).

List<string> data = new List<string> {
    "E", "B", "D", "A", "C", "B", "A", "C"
};
var preferences = new Dictionary<string, string> {
    { "A", " 01" },
    { "B", " 02" },
    { "C", " 03" }
};

string key;
IEnumerable<String> orderedData = data.OrderBy(
    item => preferences.TryGetValue(item, out key) ? key : item
);

Answer 4

Not really efficient for large lists but fairly easy to read:

public class FixedOrderComparer<T> : IComparer<T>
{
    private readonly T[] fixedOrderItems;

    public FixedOrderComparer(params T[] fixedOrderItems)
    {
        this.fixedOrderItems = fixedOrderItems;
    }

    public int Compare(T x, T y)
    {
        var xIndex = Array.IndexOf(fixedOrderItems, x);
        var yIndex = Array.IndexOf(fixedOrderItems, y);
        xIndex = xIndex == -1 ? int.MaxValue : xIndex;
        yIndex = yIndex == -1 ? int.MaxValue : yIndex;
        return xIndex.CompareTo(yIndex);
    }
}

Usage:

var orderedData = data.OrderBy(x => x, new FixedOrderComparer<string>("A", "B", "C"));

Note: Array.IndexOf<T>(....) uses EqualityComparer<T>.Default to find the target index.

Answer 5

If you put your preferences into a list, it might become easier.

List<String> data = new List<String> { "A","B","A","C","B","C","D","E" };
List<String> preferences = new List<String> { "A","B","C" };

IEnumerable<String> orderedData = data.OrderBy(
   item => preferences.IndexOf(item));

This will put all items not appearing in preferences in front because IndexOf() returns -1. An ad hoc work around might be reversing preferences and order the result descending. This becomes quite ugly, but works.

IEnumerable<String> orderedData = data.OrderByDescending(
   item => Enumerable.Reverse(preferences).ToList().IndexOf(item));

The solution becomes a bit nicer if you concat preferences and data.

IEnumerable<String> orderedData = data.OrderBy(
   item => preferences.Concat(data).ToList().IndexOf(item));

I don't like Concat() and ToList() in there. But for the moment I have no really good way around that. I am looking for a nice trick to turn the -1 of the first example into a big number.

Answer 6

Yes, you must implement your own IComparer<string> and then pass it in as the second argument of LINQ's OrderBy method.

An example can be found here: Ordering LINQ results