Check for missing number in sequence

Question

I have an List which contains 1,2,4,7,9 for example.

I have a range from 0 to 10.

Is there a way to determine what numbers are missin

Answer 1

this method here returns the number of missing elements ,sort the set , add all elements from range 0 to range max , then remove the original elements , then you will have the missing set

int makeArrayConsecutive(int[] statues) 
{

Array.Sort(statues);    
HashSet<int> set = new HashSet<int>();

for(int i = statues[0]; i< statues[statues.Length -1]; i++)
 {
  set.Add(i);
 }

for (int i = 0; i < statues.Length; i++)
{
 set.Remove(statues[i]);
}

var x = set.Count;    
return x;
// return set ; // use this if you need the actual elements + change the method return type        
}

Answer 2

Ok, really, create a new list which parallels the initial list and run the method Except over it...

I have created a fully linq answer using the Aggregate method instead to find the missings:

var list = new List<int>(new[] { 1, 2, 4, 7, 9 }); // Assumes list is ordered at this point

list.Insert(0, 0);   // No error checking, just put in the lowest and highest possibles.
list.Add(10);        // For real world processing, put in check and if not represented then add it/them.

var missing = new List<int>();    // Hold any missing values found.

list.Aggregate ((seed, aggr) =>   // Seed is the previous #, aggr is the current number.
{
    var diff = (aggr - seed) -1;  // A difference between them indicates missing.

    if (diff > 0)                 // Missing found...put in the missing range.
        missing.AddRange(Enumerable.Range((aggr - diff), diff));

    return aggr;    
});

The missing list has this after the above code has been executed:

3, 5, 6, 8

Answer 3

LINQ's Except method would be the most readable. Whether it performs adequately for you or not would be a matter for testing.

E.g.

range.Except(listOfValues);

Edit

Here's the program I used for my mini-benchmark, for others to plug away with:

static void Main()
{
    var a = Enumerable.Range(0, 1000000);
    var b = new List<int>();

    for (int i = 0; i < 1000000; i += 10)
    {
        b.Add(i);
    }

    Stopwatch sw = new Stopwatch();
    sw.Start();
    var c = a.Except(b).ToList();
    sw.Stop();
    Console.WriteLine("Milliseconds {0}", sw.ElapsedMilliseconds );
    sw.Reset();

    Console.ReadLine();
}

Answer 4

This does not use LINQ but it works in linear time.

I assume that input list is sorted.

This takes O(list.Count).

private static IEnumerable<int> get_miss(List<int> list,int length)
{
    var miss = new List<int>();
    int i =0;
    for ( i = 0; i < list.Count - 1; i++)
    {
        foreach (var item in 
                     Enumerable.Range(list[i] + 1, list[i + 1] - list[i] - 1))
        {
            yield return item;
        }

    }
    foreach (var item in Enumerable.Range(list[i]+1,length-list[i]))
    {
        yield return item;
    }
}

---

This should take O(n) where n is length of full range.

 static void Main()
    {
        List<int> identifiers = new List<int>() { 1, 2, 4, 7, 9 };

        Stopwatch sw = new Stopwatch();

        sw.Start();
        List<int> miss = GetMiss(identifiers,150000);
        sw.Stop();
        Console.WriteLine("{0}",sw.ElapsedMilliseconds);

    }
private static List<int> GetMiss(List<int> identifiers,int length)
{
    List<int> miss = new List<int>();

    int j = 0;

    for (int i = 0; i < length; i++)
    {
        if (i < identifiers[j])
            miss.Add(i);

        else if (i == identifiers[j])
            j++;

        if (j == identifiers.Count)
        {
            miss.AddRange(Enumerable.Range(i + 1, length - i));
            break;
        }
    }

    return miss;
}

Answer 5

        List<int> selectedNumbers = new List<int>(){8, 5, 3, 12, 2};

        int firstNumber = selectedNumbers.OrderBy(i => i).First();
        int lastNumber = selectedNumbers.OrderBy(i => i).Last();

        List<int> allNumbers = Enumerable.Range(firstNumber, lastNumber - firstNumber + 1).ToList();

        List<int> missingNumbers = allNumbers.Except(selectedNumbers).ToList();

        foreach (int i in missingNumbers)
        {
            Response.Write(i);
        }

Answer 6

Turn the range you want to check into a HashSet:

public IEnumerable<int> FindMissing(IEnumerable<int> values)
{
  HashSet<int> myRange = new HashSet<int>(Enumerable.Range(0,10));
  myRange.ExceptWith(values);
  return myRange;
}

Will return the values that aren't in values.