SQL query for a carriage return in a string and ultimately removing carriage return

Question

SQL query for a carriage return in a string and ultimately removing carriage return

I have some data in a table and there are some carriage returns in places where I

Answer 1

The main question was to remove the CR/LF. Using the replace and char functions works for me:

Select replace(replace(Name,char(10),''),char(13),'')

For Postgres or Oracle SQL, use the CHR function instead:

       replace(replace(Name,CHR(10),''),CHR(13),'')

Answer 2

this will be slow, but if it is a one time thing, try...

select * from parameters where name like '%'+char(13)+'%' or name like '%'+char(10)+'%'

Note that the ANSI SQL string concatenation operator is "||", so it may need to be:

select * from parameters where name like '%' || char(13) || '%' or name like '%' || char(10) || '%'

Answer 3

this works: select * from table where column like '%(hit enter)%'

Ignore the brackets and hit enter to introduce new line.

Answer 4

Something like this seems to work for me:

SELECT * FROM Parameters WHERE Name LIKE '%\n%'

Answer 5

This also works

SELECT TRANSLATE(STRING_WITH_NL_CR, CHAR(10) || CHAR(13), '  ') FROM DUAL;

Answer 6

You can also use regular expressions:

SELECT * FROM Parameters WHERE Name REGEXP '\n';