Is it possible to change an instance's method implementation without changing all other instances of the same class? [duplicate]

Answer 1

If you're binding to the instance, you shouldn't include the self argument:

>>> class Foo(object):
...     pass
... 
>>> def donothing():
...     pass
... 
>>> f = Foo()
>>> f.x = donothing
>>> f.x()
>>> 

You do need the self argument if you're binding to a class though:

>>> def class_donothing(self):
...     pass
... 
>>> foo.y = class_donothing
>>> f.y()
>>> 

Answer 2

Do Not Do This.

Changing one instance's methods is just wrong.

Here are the rules of OO Design.

1. Avoid Magic.

2. If you can't use inheritance, use delegation.

That means that every time you think you need something magic, you should have been writing a "wrapper" or Facade around the object to add the features you want.

Just write a wrapper.

Answer 3

This answer is outdated; the answer below works with modern Python

Everything you wanted to know about Python Attributes and Methods.

Yes, this is an indirect answer, but it demonstrates a number of techniques and explains some of the more intricate details and "magic".

For a "more direct" answer, consider python's new module. In particular, look at the instancemethod function which allows "binding" a method to an instance -- in this case, that would allow you to use "self" in the method.

import new
class Z(object):
  pass
z = Z() 
def method(self):
  return self
z.q = new.instancemethod(method, z, None)
z is z.q()  # true

Answer 4

If you ever need to do it for a special method (which, for a new-style class -- which is what you should always be using and the only kind in Python 3 -- is looked up on the class, not the instance), you can just make a per-instance class, e.g....:

self.foo = Foo()
meths = {'__str__': lambda self: 'peekaboo!'}
self.foo.__class__ = type('yFoo', (Foo,), meths)

Edit: I've been asked to clarify the advantages of this approach wrt new.instancemethod...:

>>> class X(object): 
...   def __str__(self): return 'baah'
... 
>>> x=X()
>>> y=X()
>>> print x, y
baah baah
>>> x.__str__ = new.instancemethod(lambda self: 'boo!', x)
>>> print x, y
baah baah

As you can see, the new.instancemethod is totally useless in this case. OTOH...:

>>> x.__class__=type('X',(X,),{'__str__':lambda self:'boo!'})
>>> print x, y
boo! baah

...assigning a new class works great for this case and every other. BTW, as I hope is clear, once you've done this to a given instance you can then later add more method and other class attributes to its x.__class__ and intrinsically affect only that one instance!

Answer 5

Since Python 2.6, you should use the types module's MethodType class:

from types import MethodType

class A(object):
    def m(self):
        print 'aaa'

a = A()

def new_m(self):
    print 'bbb'

a.m = MethodType(new_m, a)

As another answer pointed out, however, this will not work for 'magic' methods of new-style classes, such as __str__().

Answer 6

Your example is kind of twisted and complex, and I don't quite see what it has to do with your question. Feel free to clarify if you like.

However, it's pretty easy to do what you're looking to do, assuming I'm reading your question right.

class Foo(object):
    def bar(self):
        print('bar')

def baz():
    print('baz')

In an interpreter ...

>>> f = Foo()
>>> f.bar()
bar
>>> f.bar = baz
>>> f.bar()
baz
>>> g = Foo()
>>> g.bar()
bar
>>> f.bar()
baz