Failing to send email with the Python example

Question

I\'ve been trying (and failing) to figure out how to send email via Python.

Trying the example from here: http://docs.python.org/library/smtplib.html#smtplib.SMTP

Answer 1

Okay, found out that this line of code does the trick!

server = smtplib.SMTP('smtp.gmail.com', 587 )

Turned out to be GMAIL didn't support SSL on port 25 (and port 465 caused a hang for some reason).

Thanks guys!

Answer 2

You should check your port, I'm not sure that google's SMTP port is 65, that would explain the timeout.

Modify your sources as such:

smtplib.SMTP_SSL('smtp.google.com', 465)

If, however, you are certain that it ought to work and it doesn't, it appears that there are some problems with smtplib.SMTP_SSL, and there's an available patch for it here.

Answer 3

import smtplib

content = 'example email stuff here'

mail = smtplib.SMTP('smtp.gmail.com', 587)

mail.ehlo()

mail.starttls()

mail.login('email@gmail.com','password')

mail.sendmail('email@gmail.com', 'email@yahoo.com', content)

mail.close()

Answer 4

The following code works for me:

import smtplib

FROMADDR = "my.real.address@gmail.com"
LOGIN    = FROMADDR
PASSWORD = "my.real.password"
TOADDRS  = ["my.real.address@gmail.com"]
SUBJECT  = "Test"

msg = ("From: %s\r\nTo: %s\r\nSubject: %s\r\n\r\n"
       % (FROMADDR, ", ".join(TOADDRS), SUBJECT) )
msg += "some text\r\n"

server = smtplib.SMTP('smtp.gmail.com', 587)
server.set_debuglevel(1)
server.ehlo()
server.starttls()
server.login(LOGIN, PASSWORD)
server.sendmail(FROMADDR, TOADDRS, msg)
server.quit()

I'm using Python 2.5.2.

Edit: changed port from 25 to 587 as suggested by ΤΖΩΤΖΙΟΥ, and dropped the second ehlo(). Now I would love to know why port 25 works perfectly from my machine (and port 465 does not).

Answer 5

Here's a simple throw away solution. Meant to paste this earlier, but fell asleep at my chair.

import smtplib
import email
import os

username = "user@gmail.com"
passwd = "password"

def mail(to, subject, text, attach):
   msg = MIMEMultipart()

   msg['From'] = username
   msg['To'] = to
   msg['Subject'] = subject

   msg.attach(MIMEText(text)) 

   part = MIMEBase('application', 'octet-stream')
   part.set_payload(open(attach, 'rb').read())
   Encoders.encode_base64(part)
   part.add_header('Content-Disposition',
           'attachment; filename="%s"' % os.path.basename(attach))
   msg.attach(part)

   server = smtplib.SMTP("smtp.gmail.com", 495)
   server.ehlo()
   server.starttls()
   server.ehlo()
   server.login(username, passwd)
   server.sendmail(username, to, msg.as_string())
   server.close()

mail("you", "hi", "hi", "webcam.jpg")

It's my assumption that most people on this thread that have had successful attempts with their code aren't on win32. ;)

*edit: See http://docs.python.org/library/email-examples.html for some good "official" examples.

Answer 6

from smtplib import SMTP_SSL as SMTP
from email.mime.text import MIMEText

HOST = 'smtp.gmail.com'
PORT = 465

USERNAME = 'oltjano13@gmail.com'
PASSWORD = ''

SENDER = 'oltjano13@gmail.com'
RECIPIENT = 'oltjano13@gmail.com'

text_subtype = 'plain'

with open('textfile', 'rb') as f:
    msg = MIMEText(f.read(), text_subtype)


msg['Subject'] = 'Python Script'
msg['From'] = SENDER
msg['To'] = RECIPIENT

try:
    connection = SMTP(HOST, PORT)
    connection.login(USERNAME, PASSWORD)
    connection.sendmail(SENDER, RECIPIENT, msg.as_string())
except Exception, e:
    print(e)

The above code works fine for me. As you can see the PORT = 465 is being used in this example since I am using SSL. If you plan to use the port 587 then TLS is required.