How can I scroll a div to be visible in ReactJS?

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梦如初夏
梦如初夏 2020-12-04 15:25

I have a popup list which is a div that contains a vertical list of child divs. I have added up/down keyboard navigation to change which child is

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  • 2020-12-04 15:48

    I had a NavLink that I wanted to when clicked will scroll to that element like named anchor does. I implemented it this way.

     <NavLink onClick={() => this.scrollToHref('plans')}>Our Plans</NavLink>
      scrollToHref = (element) =>{
        let node;
        if(element === 'how'){
          node = ReactDom.findDOMNode(this.refs.how);
          console.log(this.refs)
        }else  if(element === 'plans'){
          node = ReactDom.findDOMNode(this.refs.plans);
        }else  if(element === 'about'){
          node = ReactDom.findDOMNode(this.refs.about);
        }
    
        node.scrollIntoView({block: 'start', behavior: 'smooth'});
    
      }
    

    I then give the component I wanted to scroll to a ref like this

    <Investments ref="plans"/>
    
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  • 2020-12-04 15:50

    For React 16, the correct answer is different from earlier answers:

    class Something extends Component {
      constructor(props) {
        super(props);
        this.boxRef = React.createRef();
      }
    
      render() {
        return (
          <div ref={this.boxRef} />
        );
      }
    }
    

    Then to scroll, just add (after constructor):

    componentDidMount() {
      if (this.props.active) { // whatever your test might be
        this.boxRef.current.scrollIntoView();
      }
    }
    

    Note: You must use '.current,' and you can send options to scrollIntoView:

    scrollIntoView({
      behavior: 'smooth',
      block: 'center',
      inline: 'center',
    });
    

    (Found at http://www.albertgao.xyz/2018/06/07/scroll-a-not-in-view-component-into-the-view-using-react/)

    Reading the spec, it was a little hard to suss out the meaning of block and inline, but after playing with it, I found that for a vertical scrolling list, block: 'end' made sure the element was visible without artificially scrolling the top of my content off the viewport. With 'center', an element near the bottom would be slid up too far and empty space appeared below it. But my container is a flex parent with justify: 'stretch' so that may affect the behavior. I didn't dig too much further. Elements with overflow hidden will impact how the scrollIntoView acts, so you'll probably have to experiment on your own.

    My application has a parent that must be in view and if a child is selected, it then also scrolls into view. This worked well since parent DidMount happens before child's DidMount, so it scrolls to the parent, then when the active child is rendered, scrolls further to bring that one in view.

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  • 2020-12-04 15:51

    I'm just adding another bit of info for others searching for a Scroll-To capability in React. I had tied several libraries for doing Scroll-To for my app, and none worked from my use case until I found react-scrollchor, so I thought I'd pass it on. https://github.com/bySabi/react-scrollchor

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  • 2020-12-04 15:53

    Just in case someone stumbles here, I did it this way

      componentDidMount(){
        const node = this.refs.trackerRef;
        node && node.scrollIntoView({block: "end", behavior: 'smooth'})
      }
      componentDidUpdate() {
        const node = this.refs.trackerRef;
        node && node.scrollIntoView({block: "end", behavior: 'smooth'})
      }
    
      render() {
        return (
    
          <div>
            {messages.map((msg, index) => {
              return (
                <Message key={index} msgObj={msg}
                  {/*<p>some test text</p>*/}
                </Message>
              )
            })}
    
            <div style={{height: '30px'}} id='#tracker' ref="trackerRef"></div>
          </div>
        )
      }
    

    scrollIntoView is native DOM feature link

    It will always shows tracker div

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  • 2020-12-04 16:04

    I assume that you have some sort of List component and some sort of Item component. The way I did it in one project was to let the item know if it was active or not; the item would ask the list to scroll it into view if necessary. Consider the following pseudocode:

    class List extends React.Component {
      render() {
        return <div>{this.props.items.map(this.renderItem)}</div>;
      }
    
      renderItem(item) {
        return <Item key={item.id} item={item}
                     active={item.id === this.props.activeId}
                     scrollIntoView={this.scrollElementIntoViewIfNeeded} />
      }
    
      scrollElementIntoViewIfNeeded(domNode) {
        var containerDomNode = React.findDOMNode(this);
        // Determine if `domNode` fully fits inside `containerDomNode`.
        // If not, set the container's scrollTop appropriately.
      }
    }
    
    class Item extends React.Component {
      render() {
        return <div>something...</div>;
      }
    
      componentDidMount() {
        this.ensureVisible();
      }
    
      componentDidUpdate() {
        this.ensureVisible();
      }
    
      ensureVisible() {
        if (this.props.active) {
          this.props.scrollIntoView(React.findDOMNode(this));
        }
      }
    }
    

    A better solution is probably to make the list responsible for scrolling the item into view (without the item being aware that it's even in a list). To do so, you could add a ref attribute to a certain item and find it with that:

    class List extends React.Component {
      render() {
        return <div>{this.props.items.map(this.renderItem)}</div>;
      }
    
      renderItem(item) {
        var active = item.id === this.props.activeId;
        var props = {
          key: item.id,
          item: item,
          active: active
        };
        if (active) {
          props.ref = "activeItem";
        }
        return <Item {...props} />
      }
    
      componentDidUpdate(prevProps) {
        // only scroll into view if the active item changed last render
        if (this.props.activeId !== prevProps.activeId) {
          this.ensureActiveItemVisible();
        }
      }
    
      ensureActiveItemVisible() {
        var itemComponent = this.refs.activeItem;
        if (itemComponent) {
          var domNode = React.findDOMNode(itemComponent);
          this.scrollElementIntoViewIfNeeded(domNode);
        }
      }
    
      scrollElementIntoViewIfNeeded(domNode) {
        var containerDomNode = React.findDOMNode(this);
        // Determine if `domNode` fully fits inside `containerDomNode`.
        // If not, set the container's scrollTop appropriately.
      }
    }
    

    If you don't want to do the math to determine if the item is visible inside the list node, you could use the DOM method scrollIntoView() or the Webkit-specific scrollIntoViewIfNeeded, which has a polyfill available so you can use it in non-Webkit browsers.

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  • 2020-12-04 16:07

    To build on @Michelle Tilley's answer, I sometimes want to scroll if the user's selection changes, so I trigger the scroll on componentDidUpdate. I also did some math to figure out how far to scroll and whether scrolling was needed, which for me looks like the following:

      componentDidUpdate() {
        let panel, node;
        if (this.refs.selectedSection && this.refs.selectedItem) {
          // This is the container you want to scroll.          
          panel = this.refs.listPanel;
          // This is the element you want to make visible w/i the container
          // Note: You can nest refs here if you want an item w/i the selected item          
          node = ReactDOM.findDOMNode(this.refs.selectedItem);
        }
    
        if (panel && node &&
          (node.offsetTop > panel.scrollTop + panel.offsetHeight || node.offsetTop < panel.scrollTop)) {
          panel.scrollTop = node.offsetTop - panel.offsetTop;
        }
      }

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