php random x digit number

Question

I need to create a random number with x amount of digits.

So lets say x is 5, I need a number to be eg. 35562 If x is 3, then it would throw back something like; 463

Answer 1

you can generate any x-digit random number with mt_rand() function. mt_rand() much faster with rand() function syntax : mt_rand() or mt_rand($min , $max).

read more

example : <?php echo mt_rand(); ?>

Answer 2

I usually just use RAND() http://php.net/manual/en/function.rand.php

e.g.

rand ( 10000 , 99999 );

for your 5 digit random number

Answer 3

you people really likes to complicate things :)

the real problem is that the OP wants to, probably, add that to the end of some really big number. if not, there is no need I can think of for that to be required. as left zeros in any number is just, well, left zeroes.

so, just append the larger portion of that number as a math sum, not string.

e.g.

$x = "102384129" . complex_3_digit_random_string();

simply becomes

$x = 102384129000 + rand(0, 999);

done.

Answer 4

This function works perfectly with no repeats and desired number of digits.

$digits = '';
function randomDigits($length){
    $numbers = range(0,9);
    shuffle($numbers);
    for($i = 0; $i < $length; $i++){
        global $digits;
        $digits .= $numbers[$i];
    }
    return $digits;
}

You can call the function and pass the number of digits for example:

randomDigits(4);

sample results:

4957 8710 6730 6082 2987 2041 6721

Original script got from this gist

Answer 5

this simple script will do

$x = 4;//want number of digits for the random number
$sum = 0;


for($i=0;$i<$x;$i++)
{
    $sum = $sum + rand(0,9)*pow(10,$i);

}

echo $sum;

Answer 6

do it with a loop:

function randomWithLength($length){

    $number = '';
    for ($i = 0; $i < $length; $i++){
        $number .= rand(0,9);
    }

    return (int)$number;

}