var.replace is not a function

Question

I\'m using the below code to try to trim the string in Javascript but am getting the error mentioned in the title:

function trim(str) {
    return str.replac         


        

Answer 1

I fixed the problem.... sorry I should have put the code on how I was calling it too.... realized I accidentally was passing the object of the form field itself rather than it's value.

Thanks for your responses anyway. :)

Answer 2

In case of a number you can try to convert to string:

var stringValue = str.toString();
return stringValue.replace(/^\s+|\s+$/g,'');

Answer 3

probable issues:

• variable is NUMBER (instead of string);
  num=35; num.replace(3,'three'); =====> ERROR
num=35; num.toString().replace(3,'three'); =====> CORRECT !!!!!!
num='35'; num.replace(3,'three'); =====> CORRECT !!!!!!
• variable is object (instead of string);
• variable is not defined;

Answer 4

You should probably do some validations before you actually execute your function :

function trim(str) {
    if(typeof str !== 'string') {
        throw new Error('only string parameter supported!');
    }

    return str.replace(/^\s+|\s+$/g,'');
}

Answer 5

make sure you are passing string to "replace" method. Had same issue and solved it by passing string. You can also make it to string using toString() method.

Answer 6

You are not passing a string otherwise it would have a replace method. I hope you didnt type function trim(str) { return var.replace(blah); } instead of return str.replace.