JSON Parsing in iOS 7

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长情又很酷
长情又很酷 2020-12-04 11:25

I am creating an app for as existing website. They currently has the JSON in the following format :

[

   {
       \"id\": \"value\",
       \"array\": \"[{\         


        
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  • 2020-12-04 12:23
    NSString *post=[[NSString stringWithFormat:@"command=%@&username=%@&password=%@",@"login",@"username",@"password"]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
    
        NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://www.blablabla.com"]];
    
       [request setHTTPMethod:@"POST"];
    
       [request setValue:@"x-www-form-urlencoded" forHTTPHeaderField:@"content-type"];
        [request setHTTPBody:[NSData dataWithBytes:[post UTF8String] length:strlen([post UTF8String])]];
    
       NSData *data=[NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
    
        id jsonobject=[NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:nil];
    
        if ([jsonobject isKindOfClass:[NSDictionary class]])
        {
    
            NSDictionary *dict=(NSDictionary *)jsonobject;
            NSLog(@"dict==%@",dict);
    
        }
        else
        {
    
            NSArray *array=(NSArray *)jsonobject;
            NSLog(@"array==%@",array);
        }
    
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  • 2020-12-04 12:24

    Try this simple method....

    - (void)simpleJsonParsing
    {
        //-- Make URL request with server
        NSHTTPURLResponse *response = nil;
        NSString *jsonUrlString = [NSString stringWithFormat:@"http://domain/url_link"];
        NSURL *url = [NSURL URLWithString:[jsonUrlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
    
        //-- Get request and response though URL
        NSURLRequest *request = [[NSURLRequest alloc]initWithURL:url];
        NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:nil];
    
        //-- JSON Parsing
        NSMutableArray *result = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableContainers error:nil];
        NSLog(@"Result = %@",result);
    
        for (NSMutableDictionary *dic in result)
        {
             NSString *string = dic[@"array"];
            if (string)
            {
                 NSData *data = [string dataUsingEncoding:NSUTF8StringEncoding];
                 dic[@"array"] = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
            }
            else
            {
                 NSLog(@"Error in url response");
            }
        }
    
    }
    
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