OnPause and OnStop() called immediately after starting activity

Question

I have an activity that needs to turn screen on(if offed) when it is started. So in onCreate, I have:

this.getWindow().setFlags(
            WindowManager.La         


        

Answer 1

You said you want to implement some logic in onStop() but with such behavior app will not work correctly. you didn’t show us what exactly you have inside onStop() but I think your logic probably restarts the activity.. in that case you Can implement your logic in onStop like that:

@Override
protected void onStop(){
    super.onStop();

         //implement your code only if !STATE_OFF - to prevent infinite loop onResume <-> onStop  while screen is off                      
        DisplayManager dm = (DisplayManager) this.getSystemService(Context.DISPLAY_SERVICE);
        for (Display display : dm.getDisplays()){
               if(display.getState() != Display.STATE_OFF){

                 //implement your code only if device is not in "locked"  state     
                KeyguardManager myKM = (KeyguardManager) this.getSystemService(Context.KEYGUARD_SERVICE);
                if( !myKM.inKeyguardRestrictedInputMode())      
                    //If needed you can call finish() (call onDestroy()) and your logic will restart your activity only once.             
                    finish();                  
                    // implement your logic here (your logic probably restarts the activity)
                }
            }
        }
    }

2. other solution that may help you will be to avoid onStop() and use onWindowFocusChanged with bool hasFocus

     /**
     * Called when the current {@link Window} of the activity gains or loses
     * focus.  This is the best indicator of whether this activity is visible
     * to the user.
     */
       @Override
          public void onWindowFocusChanged(boolean hasFocus){
            super.onWindowFocusChanged(hasFocus);
            if( ! hasFocus  ){
            }
            else{
            }
          }
   

Answer 2

Try this. I have used this and it works fine

PowerManager pm = (PowerManager) getSystemService(Context.POWER_SERVICE);

        _wakeLock = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK | PowerManager.SCREEN_BRIGHT_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP,
            POWER_SERVICE);
    _wakeLock.acquire();

Answer 3

Add android:configChanges="keyboardHidden|orientation|screenSize" to you Activity in your Manifest. This may solve your problem.

Answer 4

Use WakeLocker class. It have methods to wake screen on

Answer 5

The workaround by Manish Mulimani worked for me, except I first check for the window focus and then call through to the super.onPause():

public void onPause() {
    mFocusDuringOnPause = hasWindowFocus();    
    super.onPause();
}

public void onStop() {
    super.onStop();
    if (mFocusDuringOnPause) {
        // normal scenario
    } else {
        // activity was started when screen was off or screen was on with keyguard displayed
    }
}

Answer 6

• Let us understand why the lifecycle methods are called multiple times.

Here is an important code comment documented in ActivityThread, which is responsible for executing the activities of the application process.

We accomplish this by going through the normal startup (because activities expect to go through onResume() the first time they run, before their window is displayed), and then pausing it.

Right after onResume, the activity window is attached to the window manager and onAttachedtoWindow is invoked. If the screen is on, the activity window will get focus and onWindowFocusChanged is invoked with true parameter. From docs:

Keep in mind that onResume is not the best indicator that your activity is visible to the user; a system window such as the keyguard may be in front. Use onWindowFocusChanged(boolean) to know for certain that your activity is visible to the user

In the reported issue, the screen if off. Hence activity window will not get focus, which results in activity's onPause method getting called followed by onStop method, as the activity window is not visible.

Since WindowManager.LayoutParams.FLAG_TURN_SCREEN_ON flag is set on activity window, the window manager service turns on the screen using power manager api. Following is the WindowManagerService code:

public int relayoutWindow(...) {
    ...
    toBeDisplayed = !win.isVisibleLw();
    ...
    if (toBeDisplayed) {
        ...
        if ((win.mAttrs.flags
            & WindowManager.LayoutParams.FLAG_TURN_SCREEN_ON) != 0) {
            if (DEBUG_VISIBILITY) Slog.v(TAG,
                "Relayout window turning screen on: " + win);
                win.mTurnOnScreen = true;
            }
        ...
        if (mTurnOnScreen) {
            if (DEBUG_VISIBILITY) Slog.v(TAG, "Turning screen on after layout!");
            mPowerManager.wakeUp(SystemClock.uptimeMillis());
            mTurnOnScreen = false;
        }
        ...
}

After the screen turns on onStart and onPause are called again.

Hence : onCreate - onStart - onResume - onPause - onStop - onStart - onPause.

This can be verified by locking the device and starting the activity using adb command or eclipse.

• Ideal Solution

If you start a task in onCreate you need to stop it in onDestory (if the task is still pending). Similarly for onStart it would be onStop and for onResume it would be onPause.

• Workaround

If you can't follow the above protocol, you can check the status of activity window focus using hasWindowFocus in onPause method. Normally the activity window focus status will be true in onPause. In scenarios like screen is off or screen is on with keyguard displayed, the activity window focus will be false in onPause.

boolean mFocusDuringOnPause;

public void onPause() {
    super.onPause;

    mFocusDuringOnPause = hasWindowFocus();    
}

public void onStop() {
    super.onStop();

    if(mFocusDuringOnPause) {
        // normal scenario
    } else {
        // activity was started when screen was off / screen was on with keygaurd displayed
    }
}