Comparing two bitmasks in SQL to see if any of the bits match

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清歌不尽 2020-12-04 11:04

Is there a way of comparing two bitmasks in Transact-SQL to see if any of the bits match? I\'ve got a User table with a bitmask for all the roles the user belongs to, and I\

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  • 2020-12-04 11:23

    example:

    DECLARE @Mask int
    SET @Mask = 6
    
    DECLARE @Users TABLE
    (
    ID int,
    Username varchar(50),
    Roles int
    )
    
    INSERT INTO @Users (ID, Username, Roles) 
    SELECT 1, 'Dave', 6
    UNION
    SELECT 2, 'Charlie', 2
    UNION
    SELECT 3, 'Susan', 4
    UNION
    SELECT 4, 'Nick', 1
    
    SELECT * FROM @Users WHERE Roles & @Mask > 0
    
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  • 2020-12-04 11:24

    Use the Transact-SQL bitwise AND operator "&" and compare the result to zero. Even better, instead of coding the roles as bits of an integer column, use boolean columns, one for each role. Then your query would simply be designer AND programmer friendly. If you expect the roles to change a lot over the lifetime of your application, then use a many-to-many table to map the association between users and their roles. both alternatives are more portable than relying on the existence of the bitwise-AND operator.

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  • 2020-12-04 11:29

    To find all programmers use:

    SELECT * FROM UserTable WHERE Roles & 2 = 2
    
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  • 2020-12-04 11:31
    SELECT * FROM UserTable WHERE Roles & 6 > 0
    
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  • SELECT * FROM table WHERE mask1 & mask2 > 0

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  • 2020-12-04 11:43

    The answer to your question is to use the Bitwise & like this:

    SELECT * FROM UserTable WHERE Roles & 6 != 0
    

    The 6 can be exchanged for any combination of your bitfield where you want to check that any user has one or more of those bits. When trying to validate this I usually find it helpful to write this out longhand in binary. Your user table looks like this:

            1   2   4
    ------------------
    Dave    0   1   1
    Charlie 0   1   0
    Susan   0   0   1   
    Nick    1   0   0
    

    Your test (6) is this

            1   2   4
    ------------------
    Test    0   1   1
    

    If we go through each person doing the bitwaise And against the test we get these:

            1   2   4
    ------------------
    Dave    0   1   1   
    Test    0   1   1
    Result  0   1   1 (6)
    
    Charlie 0   1   0
    Test    0   1   1
    Result  0   1   0 (2)
    
    Susan   0   0   1
    Test    0   1   1
    Result  0   0   1 (4)
    
    Nick    1   0   0
    Test    0   1   1
    Result  0   0   0 (0) 
    

    The above should demonstrate that any records where the result is not zero has one or more of the requested flags.

    Edit: Here's the test case should you want to check this

    with test (id, username, roles)
    AS
    (
        SELECT 1,'Dave',6
        UNION SELECT 2,'Charlie',2
        UNION SELECT 3,'Susan',4
        UNION SELECT 4,'Nick',1
    )
    select * from test where (roles & 6) != 0  // returns dave, charlie & susan
    

    or

    select * from test where (roles & 2) != 0 // returns Dave & Charlie
    

    or

    select * from test where (roles & 7) != 0 // returns dave, charlie, susan & nick
    
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