How to generate a GUID in Oracle?

Question

Is it possible to auto-generate a GUID into an Insert statement?

Also, what type of field should I use to store this GUID?

Answer 1

Example found on: http://www.orafaq.com/usenet/comp.databases.oracle.server/2006/12/20/0646.htm

SELECT REGEXP_REPLACE(SYS_GUID(), '(.{8})(.{4})(.{4})(.{4})(.{12})', '\1-\2-\3-\4-\5') MSSQL_GUID  FROM DUAL 

Result:

6C7C9A50-3514-4E77-E053-B30210AC1082 

Answer 2

You can run the following query

 select sys_guid() from dual
 union all
 select sys_guid() from dual
 union all 
 select sys_guid() from dual

Answer 3

It is not clear what you mean by auto-generate a guid into an insert statement but at a guess, I think you are trying to do something like the following:

INSERT INTO MY_TAB (ID, NAME) VALUES (SYS_GUID(), 'Adams');
INSERT INTO MY_TAB (ID, NAME) VALUES (SYS_GUID(), 'Baker');

In that case I believe the ID column should be declared as RAW(16);

I am doing this off the top of my head. I don't have an Oracle instance handy to test against, but I think that is what you want.