Exec a shell command in Go

Question

I\'m looking to execute a shell command in Go and get the resulting output as a string in my program. I saw the Rosetta Code version:

package main
import \"f         


        

Answer 1

None of the provided answers allow to separate stdout and stderr so I try another answer.

First you get all the info you need, if you look at the documentation of the exec.Cmd type in the os/exec package. Look here: https://golang.org/pkg/os/exec/#Cmd

Especially the members Stdin and Stdout,Stderr where any io.Reader can be used to feed stdin of your newly created process and any io.Writer can be used to consume stdout and stderr of your command.

The function Shellout in the following programm will run your command and hand you its output and error output separatly as strings:

package main

import (
    "bytes"
    "fmt"
    "log"
    "os/exec"
)

const ShellToUse = "bash"

func Shellout(command string) (error, string, string) {
    var stdout bytes.Buffer
    var stderr bytes.Buffer
    cmd := exec.Command(ShellToUse, "-c", command)
    cmd.Stdout = &stdout
    cmd.Stderr = &stderr
    err := cmd.Run()
    return err, stdout.String(), stderr.String()
}

func main() {
    err, out, errout := Shellout("ls -ltr")
    if err != nil {
        log.Printf("error: %v\n", err)
    }
    fmt.Println("--- stdout ---")
    fmt.Println(out)
    fmt.Println("--- stderr ---")
    fmt.Println(errout)
}