I know that switch
/select
statements break automatically after every case. I am wondering, in the following code:
for {
switch
this should explain it.
for{
x := 1
switch {
case x >0:
fmt.Println("sjus")
case x == 1:
fmt.Println("GFVjk")
default:
fmt.Println("daslkjh")
}
}
}
Runs forever
for{
x := 1
switch {
case x >0:
fmt.Println("sjus")
break
case x == 1:
fmt.Println("GFVjk")
default:
fmt.Println("daslkjh")
}
}
}
Again, runs forever
BUT
package main
import "fmt"
func main() {
d:
for{
x := 1
switch {
case x >0:
fmt.Println("sjus")
break d
case x == 1:
fmt.Println("GFVjk")
default:
fmt.Println("daslkjh")
}
}
}
will print sjus ... clear ?
http://play.golang.org/p/GOvnfI67ih
Just from a switch block. There's plenty of examples in Golang own code you can examine (compare inner break with outer break).
It only exits the switch block.
A hopefully illustrative example:
loop:
for {
switch expr {
case foo:
if condA {
doA()
break // like 'goto A'
}
if condB {
doB()
break loop // like 'goto B'
}
doC()
case bar:
// ...
}
A:
doX()
// ...
}
B:
doY()
// ....
This question might be too old already but I still think label makes our code become harder to read. Instead of breaking the for inside select, just set a flag for the loop and handle it inside select-case before invoking break. For example:
loop := true
for loop {
select {
case <-msg:
// do your task here
case <-ctx.Done():
loop = false
break
}
}
Break statements, The Go Programming Language Specification.
A "break" statement terminates execution of the innermost "for", "switch" or "select" statement.
BreakStmt = "break" [ Label ] .
If there is a label, it must be that of an enclosing "for", "switch" or "select" statement, and that is the one whose execution terminates (§For statements, §Switch statements, §Select statements).
L: for i < n { switch i { case 5: break L } }
Therefore, the break
statement in your example terminates the switch
statement, the "innermost" statement.