How to delete multiple rows in SQL where id = (x to y)

Question

I am trying to run a SQL query to delete rows with id\'s 163 to 265 in a table

I tried this to delete less number of rows

    DELETE FROM `table` WHE         


        

Answer 1

Delete Id from table where Id in (select id from table)

Answer 2

CREATE PROC [dbo].[sp_DELETE_MULTI_ROW]       
@CODE XML
,@ERRFLAG  CHAR(1) = '0' OUTPUT    

AS        

SET NOCOUNT ON  
SET TRANSACTION ISOLATION LEVEL READ UNCOMMITTED  

DELETE tb_SampleTest
    WHERE 
        CODE IN(
            SELECT Item.value('.', 'VARCHAR(20)')
            FROM  @CODE.nodes('RecordList/ID') AS x(Item)
            )

IF @@ROWCOUNT = 0
    SET @ERRFLAG = 200

SET NOCOUNT OFF

Get string value delete

<RecordList>
    <ID>1</ID>
    <ID>2</ID>
</RecordList>

Answer 3

You can use BETWEEN:

DELETE FROM table
where id between 163 and 265

Answer 4

Please try this:

DELETE FROM `table` WHERE id >=163 and id<= 265

Answer 5

If you need to delete based on a list, you can use IN:

DELETE FROM your_table
WHERE id IN (value1, value2, ...);

If you need to delete based on the result of a query, you can also use IN:

DELETE FROM your_table
WHERE id IN (select aColumn from ...);

(Notice that the subquery must return only one column)

If you need to delete based on a range of values, either you use BETWEEN or you use inequalities:

DELETE FROM your_table
WHERE id BETWEEN bottom_value AND top_value;

or

DELETE FROM your_table
WHERE id >= a_value AND id <= another_value;