Multiple Type Constraints in Swift

Question

Let\'s say I have these protocols:

protocol SomeProtocol {

}

protocol SomeOtherProtocol {

}

Now, if I want a function that takes a gener

Answer 1

You have two possibilities:

1. You use a where clause as indicated in Jiaaro's answer:

   func someFunc<T where T : SomeProtocol, T : SomeOtherProtocol>(arg: T) {
       // do stuff
   }
   

2. You use a protocol composition type:

   func someFunc<T : protocol<SomeProtocol, SomeOtherProtocol>>(arg: T) {
       // do stuff
   }
   

Answer 2

The evolution to Swift 3.0 brings some changes. Our two choices now look a little different.

Using a where clause in Swift 3.0:

The where clause has now moved to the end of a function signature to improve readability. So multiple protocol inheritance now looks like this:

func someFunc<T>(arg: T) where T:SomeProtocol, T:SomeOtherProtocol {

}

Using the protocol<> construct in Swift 3.0:

Composition using the protocol<> construct is being deprecated. The earlier protocol<SomeProtocol, SomeOtherProtocol> now looks like this:

func someFunc<T:SomeProtocol & SomeOtherProtocol>(arg: T) {

}

References.

More info on the changes for where are here: https://github.com/apple/swift-evolution/blob/master/proposals/0081-move-where-expression.md

And, more on the changes for the protocol<> construct are here: https://github.com/apple/swift-evolution/blob/master/proposals/0095-any-as-existential.md

Answer 3

You can use a where clause which lets you specify as many requirements as you want (all of which must be fulfilled) separated by commas

Swift 2:

func someFunc<T where T:SomeProtocol, T:SomeOtherProtocol>(arg: T) {
    // stuff
}

Swift 3 & 4:

func someFunc<T: SomeProtocol & SomeOtherProtocol>(arg: T) {
    // stuff
}

or the more powerful where clause:

func someFunc<T>(arg: T) where T:SomeProtocol, T:SomeOtherProtocol{
    // stuff
}

You can of course use protocol composition (e.g., protocol<SomeProtocol, SomeOtherProtocol> ), but it's a little less flexible.

Using where lets you deal with cases where multiple types are involved.

You may still want to compose protocols for reuse in multiple places, or just to give the composed protocol a meaningful name.

Swift 5:

func someFunc(arg: SomeProtocol & SomeOtherProtocol) { 
    // stuff
}

This feels more natural as the protocols are next to the argument.

Answer 4

Swift 3 offers up to 3 different ways to declare your function.

protocol SomeProtocol {
    /* ... */
}

protocol SomeOtherProtocol {
    /* ... */        
}

1. Using & operator

func someFunc<T: SomeProtocol & SomeOtherProtocol>(arg: T) {
    /* ... */
}

2. Using where clause

func someFunc<T>(arg: T) where T: SomeProtocol, T: SomeOtherProtocol {
    /* ... */
}

3. Using where clause and & operator

func someFunc<T>(arg: T) where T: SomeProtocol & SomeOtherProtocol {
    /* ... */        
}

---

Also note that you can use typealias in order to shorten your function declaration.

typealias RequiredProtocols = SomeProtocol & SomeOtherProtocol

func someFunc<T: RequiredProtocols>(arg: T) {
    /* ... */   
}