How do I return JSON without using a template in Django?

Question

This is related to this question: Django return json and html depending on client python

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I have a command line Python API for a Django app. When I access the a

Answer 1

In Django 1.7 this is even easier with the built-in JsonResponse.

https://docs.djangoproject.com/en/dev/ref/request-response/#jsonresponse-objects

# import it
from django.http import JsonResponse

def my_view(request):

    # do something with the your data
    data = {}

    # just return a JsonResponse
    return JsonResponse(data)

Answer 2

It looks like the Django REST framework uses the HTTP accept header in a Request in order to automatically determine which renderer to use:

http://www.django-rest-framework.org/api-guide/renderers/

Using the HTTP accept header may provide an alternative source for your "if something".

Answer 3

You could also check the request accept content type as specified in the rfc. That way you can render by default HTML and where your client accept application/jason you can return json in your response without a template being required