Regex to test if string begins with http:// or https://

Question

I\'m trying to set a regexp which will check the start of a string, and if it contains either http:// or https:// it should match it.

How c

Answer 1

^https?://

You might have to escape the forward slashes though, depending on context.

Answer 2

Your use of [] is incorrect -- note that [] denotes a character class and will therefore only ever match one character. The expression [(http)(https)] translates to "match a (, an h, a t, a t, a p, a ), or an s." (Duplicate characters are ignored.)

Try this:

^https?://

If you really want to use alternation, use this syntax instead:

^(http|https)://

Answer 3

^https?:\/\/(.*) where (.*) is match everything else after https://

Answer 4

(http|https)?:\/\/(\S+)

This works for me

Not a regex specialist, but i will try to explain the awnser.

(http|https) : Parenthesis indicates a capture group, "I" a OR statement.

\/\/ : "\" allows special characters, such as "/"

(\S+) : Anything that is not whitespace until the next whitespace

Answer 5

^ for start of the string pattern,

? for allowing 0 or 1 time repeat. ie., s? s can exist 1 time or no need to exist at all.

/ is a special character in regex so it needs to be escaped by a backslash \/

/^https?:\/\//.test('https://www.bbc.co.uk/sport/cricket'); // true

/^https?:\/\//.test('http://www.bbc.co.uk/sport/cricket'); // true

/^https?:\/\//.test('ftp://www.bbc.co.uk/sport/cricket'); // false

Answer 6

This should work

^(http|https)://