Pointer losing its value + execv compilation warning

Question

I hope I haven\'t missed a similar question.

I\'m trying to code a mini-shell of my own, using primitive C functions.

I got something that should work, but I

Answer 1

C is pass by value. So when doing this

 int searchCmd(char * cmd, char * adrCmd){

adrCmd is a copy of what had been passed in. Overwriting the copy won't change what it had been copied from in the caller.

To fix this pass down the address of adrCmd:

 int searchCmd(char * cmd, char ** padrCmd){

and use it like this:

    *padrCmd = adr;

Call searchCmd() like this:

  if(!searchCmd(splited[0], &adrCmd)){

and define and initialise adrCmd like this;

  char * adrCmd = NULL;