I have JSON object as follows:
[
{
\"Project\": {
\"id\": \"1\",
\"project_name\": \"name\"
},
\"Allocati
the best JSON Tutorial i have seen, I leared json parsing from this tutorial, hope it will help
The following is a snippet code for parsing your json string. Kindly go through it:
String response = <Your JSON String>;
String Project = null;
String AllocationDetail = null;
try {
JSONArray menuObject = new JSONArray(response);
for (int i = 0; i< menuObject.length(); i++) {
Project = menuObject.getJSONObject(i).getString("Project").toString();
System.out.println("Project="+Project);
AllocationDetail = menuObject.getJSONObject(i).getString("AllocationDetail").toString();
System.out.println("AllocationDetail="+AllocationDetail);
}
JSONObject jsonObject = new JSONObject(Project);
String id = jsonObject.getString("id");
System.out.println("id="+id);
String project_name = jsonObject.getString("project_name");
System.out.println("project_name="+project_name);
JSONArray jArray = new JSONArray(AllocationDetail);
for (int i = 0; i< jArray.length(); i++) {
String team_name = jArray.getJSONObject(i).getString("team_name").toString();
System.out.println("team_name="+team_name);
String week_percentage_work = jArray.getJSONObject(i).getString("week_percentage_work").toString();
System.out.println("week_percentage_work="+week_percentage_work);
}
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
There are two ways for parsing JSON
When your content of JSON is too complex and long enough you can prefer usin GSON its much easier to maintain than JSON parsing each value manually.
Use jsonlint.com to read your json better. It appears that the json that you have copied here is invalid.
String response = <Your JSON String>; // add your Json String here
response = response.replace("[","").replace("]",""); // Just remove all square braces
JSONObject json = new JSONObject(response); //Convert the Json into Json Object
JSONObject jProject = json.getJSONObject("Project"); // get your project object
String project_id = jProject.getString("id"); // Get the value of Id
String project_name = jProject.getString("project_name"); // get the value of Project_name
The above code can be use many times as you want to parse the Json. I know its too late, but It may help many people who are trying to find the same answer. I was trying to find the same solution, but it was too hard to use the Accepted answer because of too many lines of codes, But I got the same results with hardly few lines of codes.