You can invoke an inherited interface default method using InterfaceName.super. The rules are the same as for other super method invocations: You can invoke the inherited method that you have overridden, but you can’t directly invoke the method which the inherited method might have overridden. E.g.
interface A
{
void foo();
default void toOverride() {
System.out.println("A");
}
}
interface B extends A
{
default void toOverride() {
A.super.toOverride();
System.out.println("B");
}
}
interface C extends B
{
default void toOverride() {
A.super.toOverride();// does not work
B.super.toOverride();
System.out.println("B");
}
}
class D implements B
{
public void toOverride() {
}
public void foo() {
D.this.toOverride();
B.super.toOverride();
A.super.toOverride(); // does not work!
}
}
But if each overriding method invokes its super method you have a chain of invocations. However, keep in mind that we are talking about interfaces. An implementation can always override a default method without invoking super at all.
