I\'m trying to simply show a loading gif once the form is submitted. My code is not working correctly for the loading gif to show. You\'ll see my image for the gif is set to
What about an onclick function:
<form id="form">
<input type="text" name="firstInput">
<button type="button" name="namebutton"
onClick="$('#gif').css('visibility', 'visible');
$('#form').submit();">
</form>
Of course you can put this in a function and then trigger it with an onClick
Button inputs don't have a submit event. Try attaching the event handler to the form instead:
<script type="text/javascript">
$('#login_form').submit(function() {
$('#gif').show();
return true;
});
</script>
The show()
method only affects the display
CSS setting. If you want to set the visibility you need to do it directly. Also, the .load_button
element is a button and does not raise a submit
event. You would need to change your selector to the form
for that to work:
$('#login_form').submit(function() {
$('#gif').css('visibility', 'visible');
});
Also note that return true;
is redundant in your logic, so it can be removed.
Better and clean example using JS only
Reference: TheDeveloperBlog.com
Step 1 - Create your java script and place it in your HTML page.
<script type="text/javascript">
function ShowLoading(e) {
var div = document.createElement('div');
var img = document.createElement('img');
img.src = 'loading_bar.GIF';
div.innerHTML = "Loading...<br />";
div.style.cssText = 'position: fixed; top: 5%; left: 40%; z-index: 5000; width: 422px; text-align: center; background: #EDDBB0; border: 1px solid #000';
div.appendChild(img);
document.body.appendChild(div);
return true;
// These 2 lines cancel form submission, so only use if needed.
//window.event.cancelBubble = true;
//e.stopPropagation();
}
</script>
in your form call the java script function on submit event.
<form runat="server" onsubmit="ShowLoading()">
</form>
Soon after you submit the form, it will show you the loading image.