Python Bool and int comparison and indexing on list with boolean values

Question

Indexing on list with boolean values works fine. Though the index should be an integer.

Following is what I tried in console:

>>> l = [1,2,3         


        

Answer 1

What's going on is that booleans actually are integers. True is 1 and False is 0. Bool is a subtype of int.

>>> isinstance(True, int)
True
>>> issubclass(bool, int)
True

So it's not converting them to integers, it's just using them as integers.

(Bools are ints for historical reasons. Before a bool type existed in Python, people used the integer 0 to mean false and 1 to mean true. So when they added a bool type, they made the boolean values integers in order to maintain backward compatibility with old code that used these integer values. See for instance http://www.peterbe.com/plog/bool-is-int .)

>>> help(True)
Help on bool object:

class bool(int)
 |  bool(x) -> bool
 |  
 |  Returns True when the argument x is true, False otherwise.
 |  The builtins True and False are the only two instances of the class bool.
 |  The class bool is a subclass of the class int, and cannot be subclassed.

Answer 2

Python used to lack booleans, we just used integers, 0 for False and any other integer for True. So when booleans were added to the language, the values False and True, can be treated as the integer values 0 and 1 still by the interpreter, to help backwards compatibility. Internally, bool is a sub-class of int.

In other words, the following equations are True:

>>> False == 0
True
>>> True == 1
True
>>> isinstance(True, int)
True
>>> issubclass(bool, int)
True

and as you found out:

>>> True * 3
3

This doesn't extend to strings however.

Answer 3

The Python source documentation does not mention directly that all non-zero integers are evaluate to True when passed to an if statement, while only zero evaluates to False. You can prove it to yourself with the following code in Python:

for test_integer in range(-2, 3, ):
    if not test_integer:
        print('{} evaluates to False in Python.'.format(test_integer))
    else:
        print('{} evaluates to True in Python.'.format(test_integer))
>>>-2 evaluates to True in Python.
-1 evaluates to True in Python.
0 evaluates to False in Python.
1 evaluates to True in Python.
2 evaluates to True in Python.

Try it for as far on either side of zero as you want; this code only shows for -2, -1, 0, 1, and 2 inclusive.

Answer 4

...Booleans are a subtype of plain integers.

Source.

As you can see, False is 0 and True is 1.