How to differentiate (when overloading) between prefix and postfix forms of operator++? (C++)

Question

Because I\'ve overloaded the operator++ for an iterator class

template
typename list::iterator& list::it         


        

Answer 1

Postfix has an int argument in the signature.

Class& operator++();    //Prefix 
Class  operator++(int); //Postfix 

Answer 2

http://www.devx.com/tips/Tip/12515

class Date {
    //...
    public:
    Date& operator++(); //prefix
    Date& operator--(); //prefix
    Date operator++(int unused); //postfix
    Date operator--(int unused); //postfix
};

Answer 3

everything about operator overloading http://www.parashift.com/c++-faq-lite/operator-overloading.html

Answer 4

Write a version of the same operator overload, but give it a parameter of type int. You don't have to do anything with that parameter's value.

If you're interested in some history of how this syntax was arrived out, there's a snippet of it here.