Regular expression to match digits and basic math operators

Question

I need a regular expression that will match 0-9, (,),+,-,* and /.

Answer 1

I think you are looking for character classes

[0-9()+\-*/.]

This should match a word that contains any number from 0 to 9 or ( ,),+,- ,/ or *

Answer 2

regex  = '(?:[0-9 ()]+[*+/-])+[0-9 ()]+'
string = 'mig 2*7 5+ 43 asf 4 3+32 *33 as 0 fa 3 5+9 m (3 + 5) - 9*(99)'
re.findall(regex, string)
# answer
# [' 2*7 5+ 43 ', ' 4 3+32 *33 ', ' 3 5+9 ', ' (3 + 5) - 9*(99)'] 

Answer 3

This regex helps me, just take a note here maybe it helps others.

^[0-9+\-*\/\(\)]*$

Answer 4

If you need a regex to match an arithmetic expression like this: 3+2-24*2/2-1 you can try this:

String reg1="([0-9]+[\\+\\-\\*\\/]{1}[0-9]+)+([\\+\\-\\*\\/]{1}[0-9]+)*";

You can add the bracket where do you want if you'll edit this regex.

Answer 5

This works for mathematical expression with 4 decimal places:

^([-+]? ?(\d+(\.\d{0,4})?|\(\g<1>\))( ?[-+*\/] ?\g<1>)?)$

It's inspired in base of @ndnenkov answer.

I hope that can be useful for someone.

Answer 6

[\d\(\)\+\-\*\/\.]