Replacing occurrences of a number in multiple columns of data frame with another value in R

Question

ETA: the point of the below, by the way, is to not have to iterate through my entire set of column vectors, just in case that was a proposed solution (just

Answer 1

you want to search through the whole data frame for any value that matches the value you're trying to replace. the same way you can run a logical test like replacing all missing values with 10..

data[ is.na( data ) ] <- 10

you can also replace all 4s with 10s.

data[ data == 4 ] <- 10

at least i think that's what you're after?

and let's say you wanted to ignore the first row (since it's all letters)

# identify which columns contain the values you might want to replace
data[ , 2:3 ]

# subset it with extended bracketing..
data[ , 2:3 ][ data[ , 2:3 ] == 4 ]
# ..those were the values you're going to replace

# now overwrite 'em with tens
data[ , 2:3 ][ data[ , 2:3 ] == 4 ] <- 10

# look at the final data
data

Answer 2

Just to provide a different answer, I thought I would write up a vector-math approach:

You can create a transformation matrix (really a data frame here, but will work the same), using a the vectorized 'ifelse' statement and multiply the transformation matrix and your original data, like so:

df.Rep <- function(.data_Frame, .search_Columns, .search_Value, .sub_Value){
   .data_Frame[, .search_Columns] <- ifelse(.data_Frame[, .search_Columns]==.search_Value,.sub_Value/.search_Value,1) * .data_Frame[, .search_Columns]
    return(.data_Frame)
}

To replace all values 4 with 10 in the data frame 'data' in columns 2 through 3, you would use the function like so:

# Either of these will work.  I'm just showing options.
df.Rep(data, 2:3, 4, 10)
df.Rep(data, c("var1","var2"), 4, 10)

#   name var1 var2
# 1    a    1    3
# 2    a    2    3
# 3    a    3    3
# 4    b   10   10
# 5    b    5   10
# 6    b    6   10
# 7    c    7    5
# 8    c    8    5
# 9    c    9    5

Answer 3

Just for continuity

    data[,2:3][ data[,2:3] == 4 ] <- 10

But it looks ugly, So do it in 2 steps is better.

Answer 4

Basically data[, 2:3]==4 gave you the index for data[,2:3] instead of data:

R > data[, 2:3] ==4
       var1  var2
 [1,] FALSE FALSE
 [2,] FALSE FALSE
 [3,] FALSE FALSE
 [4,]  TRUE  TRUE
 [5,] FALSE  TRUE
 [6,] FALSE  TRUE
 [7,] FALSE FALSE
 [8,] FALSE FALSE
 [9,] FALSE FALSE

So you may try this:

R > data[,2:3][data[, 2:3] ==4]
[1] 4 4 4 4