How do you read scanf until EOF in C?

Question

I have this but once it reaches the supposed EOF it just repeats the loop and scanf again.

int main(void)
{
        char words[16];

        while(scanf(\"%1         


        

Answer 1

Scanf is pretty much always more trouble than it's worth. Here are two better ways to do what you're trying to do. This first one is a more-or-less direct translation of your code. It's longer, but you can look at it and see clearly what it does, unlike with scanf.

#include <stdio.h>
#include <ctype.h>
int main(void)
{
    char buf[1024], *p, *q;
    while (fgets(buf, 1024, stdin))
    {
        p = buf;
        while (*p)
        {
            while (*p && isspace(*p)) p++;
            q = p;
            while (*q && !isspace(*q)) q++;
            *q = '\0';
            if (p != q)
                puts(p);
            p = q;
        }
    }
    return 0;
}

And here's another version. It's a little harder to see what this does by inspection, but it does not break if a line is longer than 1024 characters, so it's the code I would use in production. (Well, really what I would use in production is tr -s '[:space:]' '\n', but this is how you implement something like that.)

#include <stdio.h>
#include <ctype.h>
int main(void)
{
    int ch, lastch = '\0';
    while ((ch = getchar()) != EOF)
    {
        if (!isspace(ch))
            putchar(ch);
        if (!isspace(lastch))
            putchar('\n');
        lastch = ch;
    }
    if (lastch != '\0' && !isspace(lastch))
        putchar('\n');
    return 0;
}