Convert object's properties and values to array of key value pairs

Question

I\'m fairly new to JavaScript and am not sure this is possible to do but basically I would like to take an object and convert it into an array of strings in the format;

Answer 1

var obj =[
            {'2018-05-07':1},
            {'2018-05-08':3},
            {'2018-05-09':2}
        ];

        for(var i of obj) {
            var key = Object.keys(i).toString();
            console.log(i,'=',i[key]);
        }

Result

:

Answer 2

obj = {
  private_key: "private-key",
  public_key: "public-key"
}

str = JSON.stringify(obj).replace(/[{}]/g, '').replace(/"/g, '').replace(/:/g, '=');
console.log("Using JSON.stringify:\n", str);

str = Object.keys(obj).map((key) => `${key}=${obj[key]}`).join(',')
console.log("Using ES6 keys/map:\n", str);

str = jQuery.param(obj).replace(/&/g,',');
console.log("Using jQuery.param:\n", str);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 3

var array = [];
for (k in o)
{
    if (o.hasOwnProperty(k))
    {
        array.push(k+"="+o[k]);
    }
}

You can then join the array for your final string.

Answer 4

var object = {
    private_key: "private-key",
    public_key: "public-key"
};

var array = [];
for (var prop in object)
    array.push(prop + "=" + object[prop]);
return array.join(','); // "private_key=private-key,public_key=public-key"

Notice the order is not guaranteed.

Answer 5

In ES6 you can use Object.entries({object1:1,object2:2});. The result is: [["object1",1],["object2",2]]

Answer 6

You're probably looking for something along the lines of

var obj = {value1: 'prop1', value2: 'prop2', value3: 'prop3'};
var arr = [];
for (var key in obj) {
    if (obj.hasOwnProperty(key)) {
        arr.push(key + '=' + obj[key]);
    }
};
var result = arr.join(',');
alert(result);

Notice that it will work fine if your values are strings; if they're complex objects then you'll need to add more code.

Or you can just use jQuery.param, which does what you want, even for complex types (although it uses the & character as the separator, instead of the comma.