Printing an int list in a single line python3

Question

I\'m new to python and I\'m trying to scan multiple numbers separated by spaces (let\'s assume \'1 2 3\' as an example) in a single line and add it to a list of int. I did i

Answer 1

For python 2.7 another trick is:

arr = [1,2,3]
for num in arr:
  print num,
# will print 1 2 3

Answer 2

Try using join on a str conversion of your ints:

print ' '.join(str(x) for x in array)

Answer 3

these will both work in Python 2.7 and Python 3.x:

>>> l = [1, 2, 3]
>>> print(' '.join(str(x) for x in l))
1 2 3
>>> print(' '.join(map(str, l)))
1 2 3

btw, array is a reserved word in Python.

Answer 4

You want to say

for i in array:
    print(i, end=" ")

The syntax i in array iterates over each member of the list. So, array[i] was trying to access array[1], array[2], and array[3], but the last of these is out of bounds (array has indices 0, 1, and 2).

You can get the same effect with print(" ".join(map(str,array))).

Answer 5

Yes that is possible in Python 3, just use * before the variable like:

print(*list)

This will print the list separated by spaces.

(where * is the unpacking operator that turns a list into positional arguments, print(*[1,2,3]) is the same as print(1,2,3), see also What does the star operator mean, in a function call?)

Answer 6

Maybe this code will help you.

>>> def sort(lists):
...     lists.sort()
...     return lists
...
>>> datalist = [6,3,4,1,3,2,9]
>>> print(*sort(datalist), end=" ")
1 2 3 3 4 6 9

you can use an empty list variable to collect the user input, with method append(). and if you want to print list in one line you can use print(*list)