NSNumberFormatter and 'th' 'st' 'nd' 'rd' (ordinal) number endings

Question

Is there a way to use NSNumberFormatter to get the \'th\' \'st\' \'nd\' \'rd\' number endings?

EDIT:

Looks like it does not exist. Here\'s what I\'m using.

Answer 1

Here's a Swift solution that cycles through the user's preferred languages until it finds one with known rules (which are pretty easy to add) for ordinal numbers:

    extension Int {
        var localizedOrdinal: String {

            func ordinalSuffix(int: Int) -> String {
                for language in NSLocale.preferredLanguages() as [String] {

                switch language {
                    case let l where l.hasPrefix("it"):
                        return "°"
                    case let l where l.hasPrefix("en"):
                        switch int {
                        case let x where x != 11 && x % 10 == 1:
                            return "st"
                        case let x where x != 12 && x % 10 == 2:
                            return "nd"
                        case let x where x != 13 && x % 10 == 3:
                            return "rd"
                        default:
                            return "th"
                        }
                    default:
                        break
                    }
                }

                return ""
            }

            return "\(self)" + ordinalSuffix(self)
        }
    }

Answer 2

This was my brute force implementation to taking a NSString* representation of the date and returning the ordinal value. I feel it's much easier to read.

NSDictionary *ordinalDates = @{
    @"1": @"1st",
    @"2": @"2nd",
    @"3": @"3rd",
    @"4": @"4th",
    @"5": @"5th",
    @"6": @"6th",
    @"7": @"7th",
    @"8": @"8th",
    @"9": @"9th",
    @"10": @"10th",
    @"11": @"11th",
    @"12": @"12th",
    @"13": @"13th",
    @"14": @"14th",
    @"15": @"15th",
    @"16": @"16th",
    @"17": @"17th",
    @"18": @"18th",
    @"19": @"19th",
    @"20": @"20th",
    @"21": @"21st",
    @"22": @"22nd",
    @"23": @"23rd",
    @"24": @"24th",
    @"25": @"25th",
    @"26": @"26th",
    @"27": @"27th",
    @"28": @"28th",
    @"29": @"29th",
    @"30": @"30th",
    @"31": @"31st" };

Answer 3

You can try this, Its well simplified.

function numberToOrdinal(n) {

  if (n==0) {
    return n;
   }
   var j = n % 10,
       k = n % 100;


   if (j == 1 && k != 11) {
       return n + "st";
   }
   if (j == 2 && k != 12) {
       return n + "nd";
   }
   if (j == 3 && k != 13) {
       return n + "rd";
   }
   return n + "th";
}

Answer 4

Here's a compact Swift extension suitable for all integer types:

extension IntegerType {
    func ordinalString() -> String {
        switch self % 10 {
        case 1...3 where 11...13 ~= self % 100: return "\(self)" + "th"
        case 1:    return "\(self)" + "st"
        case 2:    return "\(self)" + "nd"
        case 3:    return "\(self)" + "rd"
        default:   return "\(self)" + "th"
        }
    }
}

Example usage:

let numbers = (0...30).map { $0.ordinalString() }
print(numbers.joinWithSeparator(", "))

Output:

0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, 26th, 27th, 28th, 29th, 30th

Answer 5

Here's a short Int extension for the English language that also accounts for and displays negative integers correctly:

extension Int {
    func ordinal() -> String {
        let suffix: String!
        // treat negative numbers as positive for suffix
        let number = (self < 0 ? self * -1 : self)

        switch number % 10 {
        case 0:
            suffix = self != 0 ? "th" : ""
        case 1:
            suffix = "st"
        case 2:
            suffix = "nd"
        case 3:
            suffix = "rd"
        default:
            suffix = "th"
        }

        return String(self) + suffix
    }
}

Answer 6

The correct way to do this from iOS 9 onwards, is:

NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
numberFormatter.numberStyle = NSNumberFormatterOrdinalStyle;

NSLog(@"%@", [numberFormatter stringFromNumber:@(1)]); // 1st
NSLog(@"%@", [numberFormatter stringFromNumber:@(2)]); // 2nd
NSLog(@"%@", [numberFormatter stringFromNumber:@(3)]); // 3rd, etc.

Alternatively:

NSLog(@"%@", [NSString localizedStringFromNumber:@(1)
                                     numberStyle:NSNumberFormatterOrdinalStyle]); // 1st