Find the max of 3 numbers in Java with different data types

Question

Say I have the following three constants:

final static int MY_INT1 = 25;
final static int MY_INT2 = -10;
final static double MY_DOUBLE1 = 15.5;

Answer 1

Java 8 way. Works for multiple parameters:

Stream.of(first, second, third).max(Integer::compareTo).get()

Answer 2

You can do like this:

public static void main(String[] args) {

    int x=2 , y=7, z=14;
    int max1= Math.max(x,y);

    System.out.println("Max value is: "+ Math.max(max1, z)); 
}  

Answer 3

if you want to do a simple, it will be like this

// Fig. 6.3: MaximumFinder.java
// Programmer-declared method maximum with three double parameters.
import java.util.Scanner;

public class MaximumFinder
{
  // obtain three floating-point values and locate the maximum value
  public static void main(String[] args)
  {
    // create Scanner for input from command window
    Scanner input = new Scanner(System.in);

    // prompt for and input three floating-point values
    System.out.print(
      "Enter three floating-point values separated by spaces: ");
    double number1 = input.nextDouble(); // read first double
    double number2 = input.nextDouble(); // read second double
    double number3 = input.nextDouble(); // read third double

    // determine the maximum value
    double result = maximum(number1, number2, number3);

    // display maximum value
    System.out.println("Maximum is: " + result);
  }

  // returns the maximum of its three double parameters          
  public static double maximum(double x, double y, double z)     
  {                                                              
    double maximumValue = x; // assume x is the largest to start

    // determine whether y is greater than maximumValue         
    if (y > maximumValue)                                       
      maximumValue = y;                                        

    // determine whether z is greater than maximumValue         
    if (z > maximumValue)                                       
      maximumValue = z;                                        

    return maximumValue;                                        
  }                                                              
} // end class MaximumFinder

and the output will be something like this

Enter three floating-point values separated by spaces: 9.35 2.74 5.1
Maximum is: 9.35

References Java™ How To Program (Early Objects), Tenth Edition

Answer 4

I have a very simple idea:

 int smallest = Math.min(a, Math.min(b, Math.min(c, d)));

Of course, if you have 1000 numbers, it's unusable, but if you have 3 or 4 numbers, its easy and fast.

Regards, Norbert

Answer 5

Without using third party libraries, calling the same method more than once or creating an array, you can find the maximum of an arbitrary number of doubles like so

public static double max(double... n) {
    int i = 0;
    double max = n[i];

    while (++i < n.length)
        if (n[i] > max)
            max = n[i];

    return max;
}

In your example, max could be used like this

final static int MY_INT1 = 25;
final static int MY_INT2 = -10;
final static double MY_DOUBLE1 = 15.5;

public static void main(String[] args) {
    double maxOfNums = max(MY_INT1, MY_INT2, MY_DOUBLE1);
}

Answer 6

Math.max only takes two arguments. If you want the maximum of three, use Math.max(MY_INT1, Math.max(MY_INT2, MY_DOUBLE2)).