Manually raising (throwing) an exception in Python

Question

How can I raise an exception in Python so that it can later be caught via an except block?

Answer 1

Another way to throw an exceptions is assert. You can use assert to verify a condition is being fulfilled if not then it will raise AssertionError. For more details have a look here.

def avg(marks):
    assert len(marks) != 0,"List is empty."
    return sum(marks)/len(marks)

mark2 = [55,88,78,90,79]
print("Average of mark2:",avg(mark2))

mark1 = []
print("Average of mark1:",avg(mark1))

Answer 2

You should learn the raise statement of python for that. It should be kept inside the try block. Example -

try:
    raise TypeError            #remove TypeError by any other error if you want
except TypeError:
    print('TypeError raised')