I have defined a JavaScript variables called myData
which is a new Array
like this:
var myData = new Array([\'2013-01-22\', 0], [\'
I would use reduce
var myData = new Array(['2013-01-22', 0], ['2013-01-29', 0], ['2013-02-05', 0], ['2013-02-12', 0], ['2013-02-19', 0], ['2013-02-26', 0], ['2013-03-05', 0], ['2013-03-12', 0], ['2013-03-19', 0], ['2013-03-26', 0], ['2013-04-02', 21], ['2013-04-09', 2]);
var sum = myData.reduce(function(a, b) {
return a + b[1];
}, 0);
$("#result").text(sum);
Available on jsfiddle
You can use the native map method for Arrays. map Method (Array) (JavaScript)
var myData = new Array(['2013-01-22', 0], ['2013-01-29', 0], ['2013-02-05', 0],
['2013-02-12', 0], ['2013-02-19', 0], ['2013-02-26', 0],
['2013-03-05', 0], ['2013-03-12', 0], ['2013-03-19', 0],
['2013-03-26', 0], ['2013-04-02', 21], ['2013-04-09', 2]);
var a = 0;
myData.map( function(aa){ a += aa[1]; return a; });
a is your result
Creating a sum method would work nicely, e.g. you could add the sum function to Array
Array.prototype.sum = function(selector) {
if (typeof selector !== 'function') {
selector = function(item) {
return item;
}
}
var sum = 0;
for (var i = 0; i < this.length; i++) {
sum += parseFloat(selector(this[i]));
}
return sum;
};
then you could do
> [1,2,3].sum()
6
and in your case
> myData.sum(function(item) { return item[1]; });
23
Edit: Extending the builtins can be frowned upon because if everyone did it we would get things unexpectedly overriding each other (namespace collisions). you could add the sum function to some module and accept an array as an argument if you like.
that could mean changing the signature to myModule.sum = function(arr, selector) {
then this
would become arr
Try the following
var myData = [['2013-01-22', 0], ['2013-01-29', 1], ['2013-02-05', 21]];
var myTotal = 0; // Variable to hold your total
for(var i = 0, len = myData.length; i < len; i++) {
myTotal += myData[i][1]; // Iterate over your first array and then grab the second element add the values up
}
document.write(myTotal); // 22 in this instance