PHP - count specific array values

Question

How can I count the number of element inside an array with value equals a constant? example,

$myArray = array(\"Kyle\",\"Ben\",\"Sue\",\"Phil\",\"Ben\",\"Mar         


        

Answer 1

Use array_count_values() function . Check this link http://php.net/manual/en/function.array-count-values.php

Answer 2

$array = array("Kyle","Ben","Sue","Phil","Ben","Mary","Sue","Ben");
$counts = array_count_values($array);
echo $counts['Ben'];

Answer 3

define( 'SEARCH_STRING', 'Ben' );

$myArray = array("Kyle","Ben","Sue","Phil","Ben","Mary","Sue","Ben");

$count = count(array_filter($myArray,function($value){return SEARCH_STRING === $value;}));

echo $count, "\n";

Output:

3

Answer 4

array_count_values only works for integers and strings. If you happen to want counts for float/numeric values (and you are heedless of small variations in precision or representation), this works:

function arrayCountValues($arr) {
  $vals = [];
  foreach ($arr as $val) { array_push($vals,strval($val)); }
  $cnts = array_count_values($vals);
  arsort($cnts);
  return $cnts;
}

Note that I return $cnts with the keys as strings. It would be easy to reconvert them, but I'm trying to determine the mode for the values, so I only need to re-convert the first (several) values.

I tested a version which looped, creating an array of counts rather than using array_count_values, and this turned out to be more efficient (by maybe 8-10%)!