Find all CSV files in a directory using Python

Question

How can I find all files in directory with the extension .csv in python?

Answer 1

import os

path = 'C:/Users/Shashank/Desktop/'
os.chdir(path)

for p,n,f in os.walk(os.getcwd()):
    for a in f:
        a = str(a)
        if a.endswith('.csv'):
            print(a)
            print(p)

This will help to identify path also of these csv files

Answer 2

You could just use glob.glob with recursive = true, the pattern ** will match any files and zero or more directories, subdirectories and symbolic links to directories.

import glob, os

os.chdir("C:\\Users\\username\\Desktop\\MAIN_DIRECTORY")

for file in glob.glob("*/.csv", recursive = true):
    print(file)

Answer 3

I had to get csv files that were in subdirectories, therefore, using the response from tchlpr I modified it to work best for my use case:

import os
import glob

os.chdir( '/path/to/main/dir' )
result = glob.glob( '*/**.csv' )
print( result )

Answer 4

import os
import glob

path = 'c:\\'
extension = 'csv'
os.chdir(path)
result = glob.glob('*.{}'.format(extension))
print(result)

Answer 5

This solution uses the python function filter. This function creates a list of elements for which a function returns true. In this case, the anonymous function used is partial matching '.csv' on every element of the directory files list obtained with os.listdir('the path i want to look in')

import os

filepath= 'filepath_to_my_CSVs'  # for example: './my_data/'

list(filter(lambda x: '.csv' in x, os.listdir('filepath_to_my_CSVs')))