[removed] replace last occurrence of text in a string

Question

See my code snippet below:

var list = [\'one\', \'two\', \'three\', \'four\'];
var str = \'one two, one three, one four, one\';
for ( var i = 0; i < list.         


        

Answer 1

You can use String#lastIndexOf to find the last occurrence of the word, and then String#substring and concatenation to build the replacement string.

n = str.lastIndexOf(list[i]);
if (n >= 0 && n + list[i].length >= str.length) {
    str = str.substring(0, n) + "finish";
}

...or along those lines.

Answer 2

Couldn't you just reverse the string and replace only the first occurrence of the reversed search pattern? I'm thinking . . .

var list = ['one', 'two', 'three', 'four'];
var str = 'one two, one three, one four, one';
for ( var i = 0; i < list.length; i++)
{
     if (str.endsWith(list[i])
     {
         var reversedHaystack = str.split('').reverse().join('');
         var reversedNeedle = list[i].split('').reverse().join('');

         reversedHaystack = reversedHaystack.replace(reversedNeedle, 'hsinif');
         str = reversedHaystack.split('').reverse().join('');
     }
 }