Open a selected file (image, pdf, …) programmatically from my Android Application?

Question

I\'m working on an Android application which should be able to open a selected file from a specific folder.

I already tried this, but after selecting which applicati

Answer 1

To Open a File in Android Programatically,you can use this code :- We use File Provider for internal file access .You can also see details about File Provider here in this linkfileprovidr1,file provider2,file provider3. Create a File Provider and defined in Manifest File .

<provider
    android:name="android.support.v4.content.FileProvider"
    android:authorities="com.packagename.app.fileprovider"
    android:exported="false"
    android:grantUriPermissions="true">

    <meta-data
        android:name="android.support.FILE_PROVIDER_PATHS"
        android:resource="@xml/file_paths">
    </meta-data>

</provider>

Define file_path in resources file.

<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
    <external-path
        name="my_images"
        path="Android/data/com.packagename.app/files/Pictures" />

    <external-files-path name="vivalinkComProp" path="Android/data/com.vivalink.app/vivalinkComProp/docs"/>
    <external-path
        name="external"
        path="." />
    <external-files-path
        name="external_files"
        path="." />
    <cache-path
        name="cache"
        path="." />
    <external-cache-path
        name="external_cache"
        path="." />
    <files-path
        name="files"
        path="." />

</paths>

Define Intent For View

String directory_path = Environment.getExternalStorageDirectory().getPath() + "/MyFile/";
String targetPdf = directory_path + fileName + ".pdf";
File filePath = new File(targetPdf);

Intent intentShareFile = new Intent(Intent.ACTION_VIEW);
File fileWithinMyDir = new File(targetPdf);
Uri bmpUri = FileProvider.getUriForFile(activity, "com.packagename.app.fileprovider", filePath);
if (fileWithinMyDir.exists()) {
    intentShareFile.setDataAndType(bmpUri,"application/pdf");
    intentShareFile.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    intentShareFile.setFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION | Intent.FLAG_ACTIVITY_CLEAR_TOP);
    startActivity(Intent.createChooser(intentShareFile, "Open File Using..."));

}

You can use different way to create a file provider in android . Hope this will help you.

Answer 2

Try the below code. I am using this code for opening a PDF file. You can use it for other files also.

File file = new File(Environment.getExternalStorageDirectory(),
                     "Report.pdf");
Uri path = Uri.fromFile(file);
Intent pdfOpenintent = new Intent(Intent.ACTION_VIEW);
pdfOpenintent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
pdfOpenintent.setDataAndType(path, "application/pdf");
try {
    startActivity(pdfOpenintent);
}
catch (ActivityNotFoundException e) {

}

If you want to open files, you can change the setDataAndType(path, "application/pdf"). If you want to open different files with the same intent, you can use Intent.createChooser(intent, "Open in...");. For more information, look at How to make an intent with multiple actions.

Answer 3

directly you can use this code it will open all type of files

Intent sharingIntent = new Intent(Intent.ACTION_VIEW);
    Uri screenshotUri = Uri.fromFile(your_file);
    sharingIntent.setType("image/png");
    sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
    String type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(MimeTypeMap.getFileExtensionFromUrl(screenshotUri.toString()));
    sharingIntent.setDataAndType(screenshotUri, type == null ? "text/plain" : type);
    startActivity(Intent.createChooser(sharingIntent, "Share using"));