How do I find the current executable filename? [duplicate]

Answer 1

Environment.GetCommandLineArgs()[0]

Answer 2

In addition to the answers above.

I wrote following test.exe as console application

static void Main(string[] args) {
  Console.WriteLine(
    System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName);
  Console.WriteLine(
    System.Reflection.Assembly.GetEntryAssembly().Location);
  Console.WriteLine(
    System.Reflection.Assembly.GetExecutingAssembly().Location);
  Console.WriteLine(
    System.Reflection.Assembly.GetCallingAssembly().Location);
}

Then I compiled the project and renamed its output to the test2.exe file. The output lines were correct and the same.

But, if I start it in the Visual Studio, the result is:

d:\test2.vhost.exe

d:\test2.exe

d:\test2.exe

C:\Windows\Microsoft.NET\Framework\v2.0.50727\mscorlib.dll

The ReSharper plug-in to the Visual Studio has underlined the

System.Diagnostics.Process.GetCurrentProcess().MainModule

as possible System.NullReferenceException. If you look into documentation of the MainModule you will find that this property can throw also NotSupportedException, PlatformNotSupportedException and InvalidOperationException.

The GetEntryAssembly method is also not 100% "safe". MSDN:

The GetEntryAssembly method can return null when a managed assembly has been loaded from an unmanaged application. For example, if an unmanaged application creates an instance of a COM component written in C#, a call to the GetEntryAssembly method from the C# component returns null, because the entry point for the process was unmanaged code rather than a managed assembly.

For my solutions, I prefer the Assembly.GetEntryAssembly().Location.

More interest is if need to solve the problem for the virtualization. For example, we have a project, where we use a Xenocode Postbuild to link the .net code into one executable. This executable must be renamed. So all the methods above didn't work, because they only gets the information for the original assembly or inner process.

The only solution I found is

var location = System.Reflection.Assembly.GetEntryAssembly().Location;
var directory = System.IO.Path.GetDirectoryName(location);
var file = System.IO.Path.Combine(directory, 
  System.Diagnostics.Process.GetCurrentProcess().ProcessName + ".exe");

Answer 3

If you want the executable:

System.Reflection.Assembly.GetEntryAssembly().Location

If you want the assembly that's consuming your library (which could be the same assembly as above, if your code is called directly from a class within your executable):

System.Reflection.Assembly.GetCallingAssembly().Location

If you'd like just the filename and not the path, use:

Path.GetFileName(System.Reflection.Assembly.GetEntryAssembly().Location)

Answer 4

This one was not included:

System.Windows.Forms.Application.ExecutablePath;

~Joe

Answer 5

System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName

Answer 6

I think this should be what you want:

System.Reflection.Assembly.GetEntryAssembly().Location

This returns the assembly that was first loaded when the process started up, which would seem to be what you want.

GetCallingAssembly won't necessarily return the assembly you want in the general case, since it returns the assembly containing the method immediately higher in the call stack (i.e. it could be in the same DLL).