Round a Floating Point Number Down to the Nearest Integer?

Question

As the title suggests, I want to take a floating point number and round it down to the nearest integer. However, if it\'s not a whole, I ALWAYS want to round down the variab

Answer 1

One of these should work:

import math
math.trunc(1.5)
> 1
math.trunc(-1.5)
> -1
math.floor(1.5)
> 1
math.floor(-1.5)
> -2

Answer 2

If you don't want to import math, you could use:

int(round(x))

Here's a piece of documentation:

>>> help(round)
Help on built-in function round in module __builtin__:

round(...)
    round(number[, ndigits]) -> floating point number

    Round a number to a given precision in decimal digits (default 0 digits).
    This always returns a floating point number.  Precision may be negative.

Answer 3

I think you need a floor function :

math.floor(x)

Answer 4

Simple

print int(x)

will work as well.

Answer 5

x//1

The // operator returns the floor of the division. Since dividing by 1 doesn't change your number, this is equivalent to floor but no import is needed. Notes:

1. This returns a float
2. This rounds towards -∞

Answer 6

I used this code where you subtract 0.5 from the number and when you round it, it is the original number rounded down.

round(a-0.5)