How do you get the path of the running script in groovy?

Question

I\'m writing a groovy script that I want to be controlled via a properties file stored in the same folder. However, I want to be able to call this script from anywhere. Wh

Answer 1

This makes sense if you are running the Groovy code as a script, otherwise the whole idea gets a little confusing, IMO. The workaround is here: https://issues.apache.org/jira/browse/GROOVY-1642

Basically this involves changing startGroovy.sh to pass in the location of the Groovy script as an environment variable.

Answer 2

One more solution. It works perfect even you run the script using GrovyConsole

File getScriptFile(){
    new File(this.class.classLoader.getResourceLoader().loadGroovySource(this.class.name).toURI())
}

println getScriptFile()

Answer 3

workaround: for us it was running in an ANT environment and storing some location parent (knowing the subpath) in the Java environment properties (System.setProperty( "dirAncestor", "/foo" )) we could access the dir ancestor via Groovy's properties.get('dirAncestor').
maybe this will help for some scenarios mentioned here.

Answer 4

For gradle user

I have same issue when I'm starting to work with gradle. I want to compile my thrift by remote thrift compiler (custom by my company).

Below is how I solved my issue:

task compileThrift {
doLast {
        def projectLocation = projectDir.getAbsolutePath(); // HERE is what you've been looking for.
        ssh.run {
            session(remotes.compilerServer) {
                // Delete existing thrift file.
                cleanGeneratedFiles()
                new File("$projectLocation/thrift/").eachFile() { f ->
                    def fileName=f.getName()
                    if(f.absolutePath.endsWith(".thrift")){
                        put from: f, into: "$compilerLocation/$fileName"
                    }
                }
                execute "mkdir -p $compilerLocation/gen-java"
                def compileResult = execute "bash $compilerLocation/genjar $serviceName", logging: 'stdout', pty: true
                assert compileResult.contains('SUCCESSFUL')
                get from: "$compilerLocation/$serviceName" + '.jar', into: "$projectLocation/libs/"
            }
        }
    }
}

Answer 5

As of Groovy 2.3.0 the @groovy.transform.SourceURI annotation can be used to populate a variable with the URI of the script's location. This URI can then be used to get the path to the script:

import groovy.transform.SourceURI
import java.nio.file.Path
import java.nio.file.Paths

@SourceURI
URI sourceUri

Path scriptLocation = Paths.get(sourceUri)

Note that this will only work the URI is a file: URI (or another URI scheme type with an installed FileSystemProvider), otherwise a FileSystemNotFoundException will be thrown by the Paths.get(URI) call. Certain Groovy runtimes such as groovyshell and nextflow will return a data: URI, which will not typically match an installed FileSystemProvider.

Answer 6

You are correct that new File(".").getCanonicalPath() does not work. That returns the working directory.

To get the script directory

scriptDir = new File(getClass().protectionDomain.codeSource.location.path).parent

To get the script file path

scriptFile = getClass().protectionDomain.codeSource.location.path