Query for documents where array size is greater than 1

Question

I have a MongoDB collection with documents in the following format:

{
  \"_id\" : ObjectId(\"4e8ae86d08101908e1000001\"),
  \"name\" : [\"Name\"],
  \"zipcod         


        

Answer 1

I found this solution, to find items with an array field greater than certain length

db.allusers.aggregate([
  {$match:{username:{$exists:true}}},
  {$project: { count: { $size:"$locations.lat" }}},
  {$match:{count:{$gt:20}}}
])

The first $match aggregate uses an argument thats true for all the documents. If blank, i would get

"errmsg" : "exception: The argument to $size must be an Array, but was of type: EOO"

Answer 2

None of the above worked for me. This one did so I'm sharing it:

db.collection.find( {arrayName : {$exists:true}, $where:'this.arrayName.length>1'} )

Answer 3

You can MongoDB aggregation to do the task:

db.collection.aggregate([
  {
    $addFields: {
      arrayLength: {$size: '$array'}
    },
  },
  {
    $match: {
      arrayLength: {$gt: 1}
    },
  },
])

Answer 4

Try to do something like this:

db.getCollection('collectionName').find({'ArrayName.1': {$exists: true}})

1 is number, if you want to fetch record greater than 50 then do ArrayName.50 Thanks.

Answer 5

db.accommodations.find({"name":{"$exists":true, "$ne":[], "$not":{"$size":1}}})

Answer 6

MongoDB 3.6 include $expr https://docs.mongodb.com/manual/reference/operator/query/expr/

You can use $expr in order to evaluate an expression inside a $match, or find.

{ $match: {
           $expr: {$gt: [{$size: "$yourArrayField"}, 0]}
         }
}

or find

collection.find({$expr: {$gte: [{$size: "$yourArrayField"}, 0]}});