JQuery allow only two numbers after decimal point

Question

I found the following JQuery function here which prevents a user from entering anything that\'s not a number or a single decimal. The function works well but I\'d like to i

Answer 1

Try this

HTML

<input type="text" id="min_rent" name="min_rent" onkeypress="return isPrice(event,$('#min_rent').val())">

Jquery

function isPrice(evt,value) {
    var charCode = (evt.which) ? evt.which : event.keyCode;
    if((value.indexOf('.')!=-1) && (charCode != 45 && (charCode < 48 || charCode > 57)))
        return false;
    else if(charCode != 45 && (charCode != 46 || $(this).val().indexOf('.') != -1) && (charCode < 48 || charCode > 57))
        return false;
    return true;
}

Worked Link demo

Answer 2

It can also be done with a regular expression:

    $('.class').on('input', function () {
        this.value = this.value.match(/^\d+\.?\d{0,2}/);
    });

Name the css selector .class to whatever you like and put it on the input.

Answer 3

The logic is every time a user entering a number you have to check two things.

1. Has the user entered decimal point?
2. Are the decimal places more than two?

For the first one you can use $(this).val().indexOf('.') != -1

For the second one you can use $(this).val().substring($(this).val().indexOf('.'), $(this).val().indexOf('.').length).length > 2

EDIT-1
Also, you have to add event.which != 0 && event.which != 8 so that arrow keys and backspace work in Firefox (Manoj comment)

EDIT-2
Also, you have to add $(this)[0].selectionStart >= text.length - 2 so that you can add digits if the cursor is to the left of the decimal point (BIdesi comment)

EDIT-3
Also, you have to check if user deleted . and placed it somewhere else creating a value with more than 2 digits after the decimal. So you have to add $this.val($this.val().substring(0, $this.val().indexOf('.') + 3)); for cutting extra digits (Gilberto Sánchez comment)

EDIT-4
To handle pasted data, you must bind a paste event handler.Then you have to check if pasted data have . withtext.indexOf('.') > -1 and more than 2 digits after the decimal with text.substring(text.indexOf('.')).length > 3. If so, you have to cut extra digits. Also you have to check that user entered numeric input with $.isNumeric() (darasd comment).

Here is the code:

$('.number').keypress(function(event) {
    var $this = $(this);
    if ((event.which != 46 || $this.val().indexOf('.') != -1) &&
       ((event.which < 48 || event.which > 57) &&
       (event.which != 0 && event.which != 8))) {
           event.preventDefault();
    }

    var text = $(this).val();
    if ((event.which == 46) && (text.indexOf('.') == -1)) {
        setTimeout(function() {
            if ($this.val().substring($this.val().indexOf('.')).length > 3) {
                $this.val($this.val().substring(0, $this.val().indexOf('.') + 3));
            }
        }, 1);
    }

    if ((text.indexOf('.') != -1) &&
        (text.substring(text.indexOf('.')).length > 2) &&
        (event.which != 0 && event.which != 8) &&
        ($(this)[0].selectionStart >= text.length - 2)) {
            event.preventDefault();
    }      
});

$('.number').bind("paste", function(e) {
var text = e.originalEvent.clipboardData.getData('Text');
if ($.isNumeric(text)) {
    if ((text.substring(text.indexOf('.')).length > 3) && (text.indexOf('.') > -1)) {
        e.preventDefault();
        $(this).val(text.substring(0, text.indexOf('.') + 3));
   }
}
else {
        e.preventDefault();
     }
});

.number {
  padding: 5px 10px;
  font-size: 16px;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" class="number" />

Answer 4

thank you! I have added the possibility of deleting the numbers and '.' once typed:

The event.keyCode !== 8 does that action for backspace.

The event.keyCode !== 46 does that action for delete.

$( document ).ready(function() {

    $('#Ds_Merchant_Amount').keypress(function(event) {
    if ((event.which != 46 || $(this).val().indexOf('.') != -1) && (event.which < 48 || event.which > 57) ) {
        if (event.keyCode !== 8 && event.keyCode !== 46 ){ //exception
            event.preventDefault();
        }
    }
    if(($(this).val().indexOf('.') != -1) && ($(this).val().substring($(this).val().indexOf('.'),$(this).val().indexOf('.').length).length>2 )){
        if (event.keyCode !== 8 && event.keyCode !== 46 ){ //exception
            event.preventDefault();
        }
    }
  });
});

Answer 5

I have updated this routine to allow standard editing features as these were prevented in the above code. (This routine is just for processing a float but can be adapted to allow only 2 digits after the decimal)

var value = $(this).val().toString();

// Allowed Keys
if (event.which === 8 || event.which === 46 // Character delete
    || event.which === 16 || event.which === 17 // Modifier Key
    || event.which === 37 || event.which === 39  // Arrow Keys
    || (event.key.toLowerCase() === "a" && event.ctrlKey) // Select All
    || (event.key.toLowerCase() === "c" && event.ctrlKey) // Copy
    || (event.key.toLowerCase() === "x" && event.ctrlKey) // Cut
    || (event.key.toLowerCase() === "v" && event.ctrlKey) // Paste
    || (event.which === 45 && event.ctrlKey) // Old school copy (CTRL + INSERT)
    || (event.which === 46 && event.shiftKey) // Old school cut (SHIFT + DELETE)
    || (event.which === 45 && event.shiftKey) // Old school paste (SHIFT + INSERT)
    || (event.which === 35) // END
    || (event.which === 36) // HOME
    || (event.which === 35 && event.shiftKey) // SHIFT + END
    || (event.which === 36 && event.shiftKey) // SHIFT + HOME
    )
{
    return;
}
else if (event.which === 190) // Process decimal point
{
    if (value == "" || value.indexOf(".") > -1)
    {
        event.preventDefault();
    }
}
else if (event.which < 48 || event.which > 57 || event.ctrlKey || event.shiftKey) // Reject anything else that isn't a number
{
    event.preventDefault();
}

Answer 6

I've updated the function for a few extra cases.

1. It will allow negative numbers
2. It will allow you to edit the left of the decimal when there are already 2 digits to the right
3. It allows you to use the arrow keys and backspace when you are in Firefox
4. It also handles pasted data

/**
 * Given an input field, this function will only allow numbers with up to two decimal places to be input.
 * @param {object} element
 * @return {number}
 */
function forceNumber(element) {
  element
    .data("oldValue", '')
    .bind("paste", function(e) {
      var validNumber = /^[-]?\d+(\.\d{1,2})?$/;
      element.data('oldValue', element.val())
      setTimeout(function() {
        if (!validNumber.test(element.val()))
          element.val(element.data('oldValue'));
      }, 0);
    });
  element
    .keypress(function(event) {
      var text = $(this).val();
      if ((event.which != 46 || text.indexOf('.') != -1) && //if the keypress is not a . or there is already a decimal point
        ((event.which < 48 || event.which > 57) && //and you try to enter something that isn't a number
          (event.which != 45 || (element[0].selectionStart != 0 || text.indexOf('-') != -1)) && //and the keypress is not a -, or the cursor is not at the beginning, or there is already a -
          (event.which != 0 && event.which != 8))) { //and the keypress is not a backspace or arrow key (in FF)
        event.preventDefault(); //cancel the keypress
      }

      if ((text.indexOf('.') != -1) && (text.substring(text.indexOf('.')).length > 2) && //if there is a decimal point, and there are more than two digits after the decimal point
        ((element[0].selectionStart - element[0].selectionEnd) == 0) && //and no part of the input is selected
        (element[0].selectionStart >= element.val().length - 2) && //and the cursor is to the right of the decimal point
        (event.which != 45 || (element[0].selectionStart != 0 || text.indexOf('-') != -1)) && //and the keypress is not a -, or the cursor is not at the beginning, or there is already a -
        (event.which != 0 && event.which != 8)) { //and the keypress is not a backspace or arrow key (in FF)
        event.preventDefault(); //cancel the keypress
      }
    });
}

forceNumber($("#myInput"));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" id="myInput" />