I know that in angular2 I can disable a button with the
[disable]
attribute, for example:
If you have a form then the following is also possible:
<form #f="ngForm">
<input name="myfield" type="text" minlenght="3" required ngModel>
<button type="submit" [disabled]="!f.valid">Submit</button>
</form>
Demo here: http://plnkr.co/edit/Xm2dCwqB9p6WygrquUGh?p=preview&open=app%2Fapp.component.ts
May be below code can help:
<button [attr.disabled]="!isValid ? true : null">Submit</button>
I think this is the easiest way
<!-- Submit Button-->
<button
mat-raised-button
color="primary"
[disabled]="!f.valid"
>
Submit
</button>
I tried using disabled along with click event. Below is the snippet , the accepted answer also worked perfectly fine , I am adding this answer to give an example how it can be used with disabled and click properties.
<button (click)="!planNextDisabled && planNext()" [disabled]="planNextDisabled"></button>
I would recommend the following.
<button [disabled]="isInvalid()">Submit</button>
I'm wondering. Why don't you want to use the [disabled]
attribute binding provided by Angular 2? It's the correct way to dealt with this situation. I propose you move your isValid
check via component method.
<button [disabled]="! isValid" (click)="onConfirm()">Confirm</button>
Basically you could use ngClass
here. But adding class wouldn't restrict event from firing. For firing up event on valid input, you should change click
event code to below. So that onConfirm
will get fired only when field is valid.
<button [ngClass]="{disabled : !isValid}" (click)="isValid && onConfirm()">Confirm</button>
Demo Here