Regex pattern including all special characters

Question

I want to write a simple regular expression to check if in given string exist any special character. My regex works but I don\'t know why it also includes all numbers, so wh

Answer 1

You can use a negative match:

Pattern regex = Pattern.compile("([a-zA-Z0-9])*"); (For zero or more characters)

or

Pattern regex = Pattern.compile("([a-zA-Z0-9])+"); (For one or more characters)

Answer 2

Try this. It works on C# it should work on java also. If you want to exclude spaces just add \s in there @"[^\p{L}\p{Nd}]+"

Answer 3

You have a dash in the middle of the character class, which will mean a character range. Put the dash at the end of the class like so:

[$&+,:;=?@#|'<>.^*()%!-]

Answer 4

Try:

(?i)^([[a-z][^a-z0-9\\s\\(\\)\\[\\]\\{\\}\\\\^\\$\\|\\?\\*\\+\\.\\<\\>\\-\\=\\!\\_]]*)$

(?i)^(A)$: indicates that the regular expression A is case insensitive.

[a-z]: represents any alphabetic character from a to z.

[^a-z0-9\\s\\(\\)\\[\\]\\{\\}\\\\^\\$\\|\\?\\*\\+\\.\\<\\>\\-\\=\\!\\_]: represents any alphabetic character except a to z, digits, and special characters i.e. accented characters.

[[a-z][^a-z0-9\\s\\(\\)\\[\\]\\{\\}\\\\^\\$\\|\\?\\*\\+\\.\\<\\>\\-\\=\\!\\_]]: represents any alphabetic(accented or unaccented) character only characters.

*: one or more occurrence of the regex that precedes it.

Answer 5

Here is my regular expression, that I used for removing all the special characters from any string :

String regex = ("[ \\\\s@  [\\\"]\\\\[\\\\]\\\\\\\0-9|^{#%'*/<()>}:`;,!& .?_$+-]+")

Answer 6

Please don't do that... little Unicode BABY ANGELs like this one