I can find tons of examples but they seem to either rely mostly on Java libraries or just read characters/lines/etc.
I just want to read in some file and get a byte
I have used below code to read a CSV file.
import scala.io.StdIn.readLine
import scala.io.Source.fromFile
readFile("C:/users/xxxx/Downloads/", "39025968_ccccc_1009.csv")
def readFile(loc :String,filenm :String): Unit ={
var flnm = fromFile(s"$loc$filenm") // Imported fromFile package
println("Files testing")
/*for (line <- flnm.getLines()) {
printf("%4d %s\n", line.length, line)
}*/
flnm.getLines().foreach(println) // getLines() is imported from readLines.
flnm.close()
}
Java 7:
import java.nio.file.{Files, Paths}
val byteArray = Files.readAllBytes(Paths.get("/path/to/file"))
I believe this is the simplest way possible. Just leveraging existing tools here. NIO.2 is wonderful.
This should work (Scala 2.8):
val bis = new BufferedInputStream(new FileInputStream(fileName))
val bArray = Stream.continually(bis.read).takeWhile(-1 !=).map(_.toByte).toArray
You might also consider using scalax.io:
scalax.io.Resource.fromFile(fileName).byteArray
The library scala.io.Source is problematic, DON'T USE IT in reading binary files.
The error can be reproduced as instructed here: https://github.com/liufengyun/scala-bug
In the file data.bin, it contains the hexidecimal 0xea, which is 11101010 in binary and should be converted to 234 in decimal.
The main.scala file contain two ways to read the file:
import scala.io._
import java.io._
object Main {
def main(args: Array[String]) {
val ss = Source.fromFile("data.bin")
println("Scala:" + ss.next.toInt)
ss.close
val bis = new BufferedInputStream(new FileInputStream("data.bin"))
println("Java:" + bis.read)
bis.close
}
}
When I run scala main.scala, the program outputs follows:
Scala:205
Java:234
The Java library generates correct output, while the Scala library not.
val is = new FileInputStream(fileName)
val cnt = is.available
val bytes = Array.ofDim[Byte](cnt)
is.read(bytes)
is.close()