I need to find the OS name and version on Unix/Linux platform. For this I tried following:
lsb_release
utility
/etc/redha
This work fine for all Linux environment.
#!/bin/sh
cat /etc/*-release
In Ubuntu:
$ cat /etc/*-release
DISTRIB_ID=Ubuntu
DISTRIB_RELEASE=10.04
DISTRIB_CODENAME=lucid
DISTRIB_DESCRIPTION="Ubuntu 10.04.4 LTS"
or 12.04:
$ cat /etc/*-release
DISTRIB_ID=Ubuntu
DISTRIB_RELEASE=12.04
DISTRIB_CODENAME=precise
DISTRIB_DESCRIPTION="Ubuntu 12.04.4 LTS"
NAME="Ubuntu"
VERSION="12.04.4 LTS, Precise Pangolin"
ID=ubuntu
ID_LIKE=debian
PRETTY_NAME="Ubuntu precise (12.04.4 LTS)"
VERSION_ID="12.04"
In RHEL:
$ cat /etc/*-release
Red Hat Enterprise Linux Server release 6.5 (Santiago)
Red Hat Enterprise Linux Server release 6.5 (Santiago)
Or Use this Script:
#!/bin/sh
# Detects which OS and if it is Linux then it will detect which Linux
# Distribution.
OS=`uname -s`
REV=`uname -r`
MACH=`uname -m`
GetVersionFromFile()
{
VERSION=`cat $1 | tr "\n" ' ' | sed s/.*VERSION.*=\ // `
}
if [ "${OS}" = "SunOS" ] ; then
OS=Solaris
ARCH=`uname -p`
OSSTR="${OS} ${REV}(${ARCH} `uname -v`)"
elif [ "${OS}" = "AIX" ] ; then
OSSTR="${OS} `oslevel` (`oslevel -r`)"
elif [ "${OS}" = "Linux" ] ; then
KERNEL=`uname -r`
if [ -f /etc/redhat-release ] ; then
DIST='RedHat'
PSUEDONAME=`cat /etc/redhat-release | sed s/.*\(// | sed s/\)//`
REV=`cat /etc/redhat-release | sed s/.*release\ // | sed s/\ .*//`
elif [ -f /etc/SuSE-release ] ; then
DIST=`cat /etc/SuSE-release | tr "\n" ' '| sed s/VERSION.*//`
REV=`cat /etc/SuSE-release | tr "\n" ' ' | sed s/.*=\ //`
elif [ -f /etc/mandrake-release ] ; then
DIST='Mandrake'
PSUEDONAME=`cat /etc/mandrake-release | sed s/.*\(// | sed s/\)//`
REV=`cat /etc/mandrake-release | sed s/.*release\ // | sed s/\ .*//`
elif [ -f /etc/debian_version ] ; then
DIST="Debian `cat /etc/debian_version`"
REV=""
fi
if [ -f /etc/UnitedLinux-release ] ; then
DIST="${DIST}[`cat /etc/UnitedLinux-release | tr "\n" ' ' | sed s/VERSION.*//`]"
fi
OSSTR="${OS} ${DIST} ${REV}(${PSUEDONAME} ${KERNEL} ${MACH})"
fi
echo ${OSSTR}
With perl and Linux::Distribution, the cleanest solution for an old problem :
#!/bin/sh
perl -e '
use Linux::Distribution qw(distribution_name distribution_version);
my $linux = Linux::Distribution->new;
if(my $distro = $linux->distribution_name()) {
my $version = $linux->distribution_version();
print "you are running $distro";
print " version $version" if $version;
print "\n";
} else {
print "distribution unknown\n";
}
'
The "lsb_release" command provides certain Linux Standard Base and distribution-specific information. So using the below command we can get Operating system name and operating system version.
"lsb_release -a"
I prepared following commands to find concise information about a Linux system:
clear
echo "\n----------OS Information------------"
hostnamectl | grep "Static hostname:"
hostnamectl | tail -n 3
echo "\n----------Memory Information------------"
cat /proc/meminfo | grep MemTotal
echo "\n----------CPU Information------------"
echo -n "Number of core(s): "
cat /proc/cpuinfo | grep "processor" | wc -l
cat /proc/cpuinfo | grep "model name" | head -n 1
echo "\n----------Disk Information------------"
echo -n "Total Size: "
df -h --total | tail -n 1| awk '{print $2}'
echo -n "Used: "
df -h --total | tail -n 1| awk '{print $3}'
echo -n "Available: "
df -h --total | tail -n 1| awk '{print $4}'
echo "\n-------------------------------------\n"
Copy and paste in an sh file like info.sh and then run it using command sh info.sh
Following command worked out for me nicely. It gives you the OS name and version.
lsb_release -a
With quotes:
cat /etc/*-release | grep "PRETTY_NAME" | sed 's/PRETTY_NAME=//g'
gives output as:
"CentOS Linux 7 (Core)"
Without quotes:
cat /etc/*-release | grep "PRETTY_NAME" | sed 's/PRETTY_NAME=//g' | sed 's/"//g'
gives output as:
CentOS Linux 7 (Core)