Right now, I have a program containing a piece of code that looks like this:
while (arrayList.iterator().hasNext()) {
//value is equal to a String value
You could also do a for loop as you would for an array but instead of array[i] you would use list.get(i)
for (int i = 0; i < list.size(); i++) {
System.out.println(list.get(i));
}
While I agree that the accepted answer is usually the best solution and definitely easier to use, I noticed no one displayed the proper usage of the iterator. So here is a quick example:
Iterator<Object> it = arrayList.iterator();
while(it.hasNext())
{
Object obj = it.next();
//Do something with obj
}
Efficient way to iterate your ArrayList
followed by this link. This type will improve the performance of looping during iteration
int size = list.size();
for(int j = 0; j < size; j++) {
System.out.println(list.get(i));
}
Apart of larsmans answer (who is indeed correct), the exception in a call to a get() method, so the code you have posted is not the one that is causing the error.
Am I doing that right, as far as iterating through the Arraylist goes?
No: by calling iterator
twice in each iteration, you're getting new iterators all the time.
The easiest way to write this loop is using the for-each construct:
for (String s : arrayList)
if (s.equals(value))
// ...
As for
java.lang.ArrayIndexOutOfBoundsException: -1
You just tried to get element number -1
from an array. Counting starts at zero.
List<String> arrayList = new ArrayList<String>();
for (String s : arrayList) {
if(s.equals(value)){
//do something
}
}
or
for (int i = 0; i < arrayList.size(); i++) {
if(arrayList.get(i).equals(value)){
//do something
}
}
But be carefull ArrayList can hold null values. So comparation should be
value.equals(arrayList.get(i))
when you are sure that value is not null or you should check if given element is null.