from mechanize import Browser
br = Browser()
br.open(\'http://somewebpage\')
html = br.response().readlines()
for line in html:
print line
When p
I haven't thought much about the cases it will miss, but you can do a simple regex:
re.sub('<[^<]+?>', '', text)
For those that don't understand regex, this searches for a string <...>, where the inner content is made of one or more (+) characters that isn't a <. The ? means that it will match the smallest string it can find. For example given <p>Hello</p>, it will match <'p> and </p> separately with the ?. Without it, it will match the entire string <..Hello..>.
If non-tag < appears in html (eg. 2 < 3), it should be written as an escape sequence &... anyway so the ^< may be unnecessary.
You can use BeautifulSoup get_text() feature.
from bs4 import BeautifulSoup
html_str = '''
<td><a href="http://www.fakewebsite.com">Please can you strip me?</a>
<br/><a href="http://www.fakewebsite.com">I am waiting....</a>
</td>
'''
soup = BeautifulSoup(html_str)
print(soup.get_text())
#or via attribute of Soup Object: print(soup.text)
It is advisable to explicitly specify the parser, for example as BeautifulSoup(html_str, features="html.parser"), for the output to be reproducible.