Does anybody know how to extract a column from a multi-dimensional array in Python?
I prefer the next hint:
having the matrix named matrix_a
and use column_number
, for example:
import numpy as np
matrix_a = np.array([[1,2,3,4],[5,6,7,8],[9,10,11,12]])
column_number=2
# you can get the row from transposed matrix - it will be a column:
col=matrix_a.transpose()[column_number]
Despite using zip(*iterable)
to transpose a nested list, you can also use the following if the nested lists vary in length:
map(None, *[(1,2,3,), (4,5,), (6,)])
results in:
[(1, 4, 6), (2, 5, None), (3, None, None)]
The first column is thus:
map(None, *[(1,2,3,), (4,5,), (6,)])[0]
#>(1, 4, 6)
One more way using matrices
>>> from numpy import matrix
>>> a = [ [1,2,3],[4,5,6],[7,8,9] ]
>>> matrix(a).transpose()[1].getA()[0]
array([2, 5, 8])
>>> matrix(a).transpose()[0].getA()[0]
array([1, 4, 7])
>>> import numpy as np
>>> A = np.array([[1,2,3,4],[5,6,7,8]])
>>> A
array([[1, 2, 3, 4],
[5, 6, 7, 8]])
>>> A[:,2] # returns the third columm
array([3, 7])
See also: "numpy.arange" and "reshape" to allocate memory
Example: (Allocating a array with shaping of matrix (3x4))
nrows = 3
ncols = 4
my_array = numpy.arange(nrows*ncols, dtype='double')
my_array = my_array.reshape(nrows, ncols)
let's say we have n X m
matrix(n
rows and m
columns) say 5 rows and 4 columns
matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16],[17,18,19,20]]
To extract the columns in python, we can use list comprehension like this
[ [row[i] for row in matrix] for in range(4) ]
You can replace 4 by whatever number of columns your matrix has. The result is
[ [1,5,9,13,17],[2,10,14,18],[3,7,11,15,19],[4,8,12,16,20] ]
Could it be that you're using a NumPy array? Python has the array module, but that does not support multi-dimensional arrays. Normal Python lists are single-dimensional too.
However, if you have a simple two-dimensional list like this:
A = [[1,2,3,4],
[5,6,7,8]]
then you can extract a column like this:
def column(matrix, i):
return [row[i] for row in matrix]
Extracting the second column (index 1):
>>> column(A, 1)
[2, 6]
Or alternatively, simply:
>>> [row[1] for row in A]
[2, 6]