Preg_match_all <a

Question

Hello i want to extract links and i want a regex which givs me /portal/clients/show/entityId/2121 the nu

Answer 1

Regex for parsing links is something like this:

'/<a\s+(?:[^"'>]+|"[^"]*"|'[^']*')*href=("[^"]+"|'[^']+'|[^<>\s]+)/i'

Given how horrible that is, I would recommend using Simple HTML Dom for getting the links at least. You could then check links using some very basic regex on the link href.

Answer 2

Don't use regular expressions for proccessing xml/html. This can be done very easily using the builtin dom parser:

$doc = new DOMDocument();
$doc->loadHTML($htmlAsString);
$xpath = new DOMXPath($doc);
$nodeList = $xpath->query('//a/@href');
for ($i = 0; $i < $nodeList->length; $i++) {
    # Xpath query for attributes gives a NodeList containing DOMAttr objects.
    # http://php.net/manual/en/class.domattr.php
    echo $nodeList->item($i)->value . "<br/>\n";
}

Answer 3

Simple PHP HTML Dom Parser example:

// Create DOM from string
$html = str_get_html($links);

//or
$html = file_get_html('www.example.com');

foreach($html->find('a') as $link) {
    echo $link->href . '<br />';
}

Answer 4

This is my solution:

<?php
// get links
$website = file_get_contents("http://www.example.com"); // download contents of www.example.com
preg_match_all("<a href=\x22(.+?)\x22>", $website, $matches); // save all links \x22 = "

// delete redundant parts
$matches = str_replace("a href=", "", $matches); // remove a href=
$matches = str_replace("\"", "", $matches); // remove "

// output all matches
print_r($matches[1]);
?>

I recommend to avoid using xml-based parsers, because you will not always know, whether the document/website has been well formed.

Best regards

Answer 5

Paring links from HTML can be done using am HTML parser.

When you have all links, simple get the index of the last forward slash, and you have your number. No regex needed.

Answer 6

When "parsing" html I mostly rely on PHPQuery: http://code.google.com/p/phpquery/ rather then regex.